Answer:
286.55K
Explanation:
To convert to kelvin , add 237 .15
Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
Mole ratio Al(NO3)3 - 4/1 - 4
Mole ratio NaCl - 9/3 - 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of AlCl3
9 moles of NaCl will produce - 1/3*9 - 3 moles.
Weight of AlCl3 - 3*133.34 - 400 grams
Thus, 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
The fourth one: Gain of an electron
Hello~! Your answer iiiiisss...
B) 2 hydrogen, 1 sulfur, 4 oxygen.
<em>Here's why:</em>
The subscripts (the little numbers next to the element symbol) tells you how many atoms there are for the symbol <u><em>on the left.</em></u>
H₂ S O₄
So, there are two hydrogen atoms, one sulfur atom (beacuse there's no number next to it), and four oxygen atoms.
I hoped this helped you!
<span>B. the birth of the Industrial Revolution.
</span>Trade in the British Empire and new inventions lead to
NOT:
A. the reopening of theatres.
C. the loss of the American colonies.
<span>D. the end of Puritan rule.</span>
