Answer:
http://www.khalidshadid.com/uploads/3/9/2/0/3920808/raymond_chang-chemistry_10th_edition.pdf
Explanation:
http://www.khalidshadid.com/uploads/3/9/2/0/3920808/raymond_chang-chemistry_10th_edition.pdf
Calcium oxide CaO = 40+16 = 56
Calcium hydroxide Ca(OH)_2 = 40+16+16+1+1 = 74
The ratio 56:74 is equal to 14:x with x being the unknown mass.
56/14 = 4
74/4 = 18.5
So the answer is 18.5g assuming the water is in excess
Answer:
(1) <em>C</em> C3H7OH = 9.200 M
(2) <em>C</em> C3H7OH = 11.647 m
Explanation:
mixture:
∴ 70% = (g C3H7OH/g mix)×100
∴ 30% = (gH2O/g mix)×100
∴ δ mix = 0.79 g/mL
assuming:
⇒ V mix = (100g)×(mL/0.79g) = 126.582 mL mix = 0.1266 L mix
⇒ g C3H7OH = 70g
⇒ g H2O = 30g
∴ Mw C3H7OH = 60.1 g/mol
∴ Mw H2O = 18 g/mol
(1) Molar concentration (M):
⇒ <em>C</em> C3H7OH = ((70 g)(mol/60.1 g))/(0.1266L) = 9.200 M
(2) molal concentration (m):
⇒ <em>C </em>C3H7OH = ((70 g)(mol/60.1g))/(0.100 Kg) = 11.647 m
Answer:
1.48 × 10²⁴ atoms
Explanation:
Step 1: Calculate the moles of argon
Argon is a noble gas, whose molar mass is 39.95 g/mol. We will use this data to find the moles corresponding to 98.1 grams of argon.
Step 2: Calculate the atoms of argon
In order to calculate the number of atoms of argon in 2.46 moles of argon, we have to consider the Avogadro's number: there are 6.02 × 10²³ atoms of Ar in 1 mole of Ar.
