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butalik [34]
2 years ago
8

You have 28.5 g of iron shot that has a volume of 3.60 mL. From this information, calculate the density of iron.

Chemistry
1 answer:
laila [671]2 years ago
8 0

Answer:

\boxed {\boxed {\sf \rho \approx 7.917 \ g/mL}}

Explanation

Density can be found by dividing the mass by the volume.

\rho=\frac{m}{v}

We know the iron sheet has a mass of 28.5 grams and the volume is 3.60 milliliters.

m= 28.5 \ g \\d= 3.60 \ mL

Substitute the values into the formula.

\rho=\frac{28.5 \ g}{ 3.60 \ mL}

Divide.

\rho = 7.91666667 \ g/mL

Let's round to the nearest thousandth.

The 6 in the ten-thousandth tells us to round the 6 to a 7.

\rho \approx 7.917 \ g/mL

The density of iron is about <u>7.917 grams per milliliter.</u>

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Answer:

W = 6.65 \cdot 10^{6} lbf

Explanation:

To find the weight (W) of the pond contents first we need to use the following equation:

W = m\cdot g   (1)

Where m the mass and g is the gravity  

Also, we have that the mass is:

m = \rho*V  (2)    

Where ρ is the density and V the volume

We cand calculate the volume as follows:

V = L*w*d   (3)

Where L is the length, w is the wide and d is the depth  

By entering equation (2) and (3) into (1) we have:

W = \rho*L*w*d*g

W = 75.3 lbm/ft^{3}*50 m*25 m*2 m*9.81 m/s^{2}  

W = 75.3 lbm/ft^{3}*\frac{(1 ft)^{3}}{(0.3048 m)^{3}}*\frac{0.454 kg}{1 lbm}*50 m*25 m*2 m*9.81 m/s^{2} = 2.96 \cdot 10^{7} N}*\frac{0.2248 lbf}{1 N} = 6.65\cdot 10^{6} lbf              

Therefore, the weight of the pond is 6.65x10⁶ lbf.

I hope it helps you!

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3 years ago
Pls help me on this it’s past due ty
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Answer:

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