Write an balance the equation
Na2O + H2O -> 2 NaOH
Calculate the molecular mass of Na2O and NaOH from the atomic mass from the periodic table.
Na = 23
O=16
H=1
Na2O = 23 * 2 + 16 = 62
NaOH = 23+16+1= 40
For the stoichiometry of the reaction one mole of Na2O = 62g produce two mol of NaOH = 2* 40= 80 g
120 g Na2O x 80g NaOH / 62g Na2O=
154.8 g NaOH
D. It will lose 2 electrons in order to become stable.
Cost per mole
Table salt : Rs 0.878
Table sugar : Rs 23.63
<h3>Further explanation</h3>
Given
Cost table salt (NaCl) = 15/kg
Cost table sugar(sucrose-C12H22O11) = 69/kg
Required
cost per mole
Solution
mol of 1 kg Table salt(NaCl ,MW= 58.5 g/mol) :

mol of 1 kg Table sugar(C12H22O11 ,MW= 342 g/mol) :

Matter - anything with mass and occupies space
accuracy - an indication of how close a measurement is to the correct result
precision - the degree to which a measurement can be replicated
meniscus - the curved top surface of a liquid column
volume - spaced occupied measured in cubic units
density - mass of an object per unit volume
Answer:
In 7.80 g of styrene, we have 3.60×10²³ atoms of H
Explanation:
Empirical formula of styrene is CH
Molecular formula of styrene is C₈H₈
So, 1 mol of styrene has 8 moles of C and 8 moles of H and 1 mol weighs 104.14 grams. Let's make a rule of three:
104.14 g (1 mol of C₈H₈) have 8 moles of H
Then 7.80 g would have ( 7.80 .8) / 104.14 = 0.599 moles
As we know, 1 mol of anything has NA particles (Avogadro's Number, 6.02×10²³), so 0.599 moles will have (mol . NA) particles
0.599 mol . 6.02×10²³ atoms / 1 mol = 3.60×10²³ atoms