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dalvyx [7]
3 years ago
13

Calculate the pH at of a 0.10 Msolution of anilinium chloride . Note that aniline is a weak base with a of . Round your answer t

o decimal place. Clears your work. Undoes your last action. Provides information about entering answers.
Chemistry
1 answer:
notsponge [240]3 years ago
8 0

The question is incomplete, here is the complete question:

Calculate the pH at of a 0.10 M solution of anilinium chloride (C_6H_5NH_3Cl) . Note that aniline (C6H5NH2) is a weak base with a pK_b of 4.87. Round your answer to 1 decimal place.

<u>Answer:</u> The pH of the solution is 5.1

<u>Explanation:</u>

Anilinium chloride is the salt formed by the combination of a weak base (aniline) and a strong acid (HCl).

To calculate the pH of the solution, we use the equation:

pH=7-\frac{1}{2}[pK_b+\log C]

where,

pK_b = negative logarithm of weak base which is aniline = 4.87

C = concentration of the salt = 0.10 M

Putting values in above equation, we get:

pH=7-\frac{1}{2}[4.87+\log (0.10)]\\\\pH=5.06=5.1

Hence, the pH of the solution is 5.1

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electronegativity of chlorine - electronegativity of lithium =

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electronegativity of oxygen - electronegativity of sodium =

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