Answer:
47 grams CoCl needed.
Explanation:
1 mole weight of CoCl in 1 Liter solution => 1.0 molar solution
∴ 1/2 mole weight of CoCl in 1/2 Liter solution => 1.0 molar solution.
1/2 mole weight of CoCl = 1/2(94 g/mole) = 47 grams CoCl needed.
E = (hc)/(λ)
E = (6.624x10^(-27))Js x ((3×10^8)ms^(-1)) /
(77.8x10^(-9)m)
E = 2.55 x 10^(-11) J
d
