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3 years ago

Electrons are:

Chemistry

2 answers:

Zolol [24]3 years ago

8 0

A) is the correct answer

Zanzabum3 years ago

4 0

Answer:

The answer to your question is: letter A

Explanation:

A) able to move from one atom to another; the atom that loses an electron becomes positively charged and the atom that gains an electron becomes negatively charged This is the correct answer to your question, because describe characteristics of electrons.

B) charged particles that move freely between all atoms; when an atom loses an electron it becomes negatively charged . This option is wrong because when an atom loses an electron it becomes positive, so this answer is wrong.

C) negatively charged and can move between atoms; the atom that loses an electron becomes negatively charged and the atom that gains an electron becomes positively charged . This answer is wrong because it says that an atom that loses and electron becomes negatively charge and vice versa.

D) positively charged particles that when transferred between different atoms create ions that are positively charged This answer is incorrect because electrons are negatevely charged.

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How does the Sun get energy?

Nikolay [14]

The sun generates energy from a process called nuclear fusion. During nuclear fusion, the high pressure and temperature in the sun's core cause nuclei to separate from their electrons. Hydrogen nuclei fuse to form one helium atom.

8 0

3 years ago

Read 2 more answers

Given the following at 25C calculate delta Hf for HCN (g) at 25C. 2NH3 (g) +3O2 (g) + 2CH4 (g) ---> 2HCN (g) + 6H2O (g) delta

AysviL [449]

<u>Answer:</u> The $\Delta H_f$ for HCN (g) in the reaction is 135.1 kJ/mol.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]$

For the given chemical reaction:

$2NH_3(g)+3O_2(g)+2CH_4(g)\rightarrow 2HCN(g)+6H_2O(g)$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(2\times \Delta H_f_{(HCN)})+(6\times \Delta H_f_{(H_2O)})]-[(2\times \Delta H_f_{(NH_3)})+(3\times \Delta H_f_{(O_2)})+(2\times \Delta H_f_{(CH_4)})]$

We are given:

$\Delta H_f_{(H_2O)}=-241.8kJ/mol\\\Delta H_f_{(NH_3)}=-80.3kJ/mol\\\Delta H_f_{(CH_4)}=-74.6kJ/mol\\\Delta H_f_{(O_2)}=0kJ/mol\\\Delta H_{rxn}=-870.8kJ$

Putting values in above equation, we get:

$-870.8=[(2\times \Delta H_f_{(HCN)})+(6\times (-241.8))]-[(2\times (-80.3))+(3\times (0))+(2\times (-74.6))]\\\\\Delta H_f_{(HCN)}=135.1kJ$

Hence, the $\Delta H_f$ for HCN (g) in the reaction is 135.1 kJ/mol.

8 0

3 years ago

Someone help please , I’ll give brain . Question 10 !

Rudik [331]

Answer:it’s c

Explanation:

I just know it is

4 0

3 years ago

Argon-40 undergoes positron emission as shown:

Rudik [331]

Answer:

$\frac{40}{18}Ar => \frac{40}{17}Cl + \frac{0}{1}e\\$

Explanation:

3 0

4 years ago

What happens to the atomic radius when an elctron is lost

Daniel [21]

Answer:

It decreases.

Explanation:

Due to changes in the Coulombic force, the protons within the nucleus of the ion have a much easier time pulling at one fewer electrons. This way, the electrons are pulled closer to the center, causing the radius to decrease.

5 0

3 years ago