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timama [110]
4 years ago
13

Imagine you have a membrane through which oxygen can diffuse with a diffusion coefficient D = 5x10-10 m2/s. The concentration of

O2 on one side of the membrane is 5x1022 atoms/m3, and on the other side it is 3.5x1022 atoms/m3. If the membrane is 2.5x10-9 m thick, what is the diffusive flux of oxygen J?
Chemistry
1 answer:
Vesna [10]4 years ago
5 0

Answer:

3.0x10²¹ atoms/m².s

Explanation:

The diffusive flux is the rate at the diffusion happens and can be calculated by:

J = D*ΔC/e

Where D is the diffusion coefficient, ΔC is the concentration variation and e is the membrane thickness, so:

J = 5x10⁻¹⁰m²/s x (5x10²² - 3.5x10²²)atoms/m³/(2.5x10⁻⁹m)

J = 3.0x10²¹ atoms/m².s

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Answer:

B.the velocity for the forward reaction equal that of the reverse reaction

Explanation:

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3 years ago
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Katyanochek1 [597]

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36 g of water vapor takes up how many liters at room temperature and pressure of 293K and 100 K PA
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in order to make tea, 32,000 J of energy were added to 100.0g of water. what was the temperature Chang of the water? ​
mina [271]

Answer:

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Explanation:

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