Answer:
5 km = 3.107 miles
one Kilometer is equal to 0.621371 meters
so the equation is
5 km times 0.621371 m
is equal to 3.107
1) Write the balanced equation to state the molar ratios:
<span>3H2(g) + N2(g) → 2NH3(g)
=> molar ratios = 3 mol H2 : 1 mol N2 : 2 mol NH3
What volume of nitrogen is needed to produce 250.0 L of ammonia gas at STP?
First, convert the 250.0 L of NH3 to number of moles at STP .
Use the fact that 1 mole of gas at STP occupies 22.4 L
=> 250.0 L * 1mol/22.4 L = 11.16 L
Second, use the molar ratio to find the number of moles of N2 that produces 11.16 L of NH3
=> 11.16 L NH3 * [1 mol N2 / 2 mol NH3] = 5.58 mol N2
Third, convert 5.58 mol N2 into liters at STP
=> 5.58 mol N2 * [22.4 L/mol] = 124.99 liters
Answer: 124,99 liters
What volume of hydrogen is needed to produce 2.50 mol NH3 at STP?
First, find the number of moles of H2 that produce 2.50 mol by using the molar ratios:
2.50 mol NH3 * [3mol H2 / 2 mol NH3] = 3.75 mol H2
Second, convert the number of moles to liters of gas at STP:
3.75 mol * 22.4 L/mol = 84 liters of H2
Answer: 84 liters
</span>
Answer:
![Kp=3.07x10^6](https://tex.z-dn.net/?f=Kp%3D3.07x10%5E6)
Explanation:
Hello,
In this case, by knowing the given reference reactions, one could rearrange them as follows:
![2 NO(g) \leftrightarrow N_2(g) + O_2(g); Kp_2 = \frac{1}{2.3 x 10^{-19}}=4.35x10^{18}](https://tex.z-dn.net/?f=2%20NO%28g%29%20%5Cleftrightarrow%20N_2%28g%29%20%2B%20O_2%28g%29%3B%20Kp_2%20%3D%20%5Cfrac%7B1%7D%7B2.3%20x%2010%5E%7B-19%7D%7D%3D4.35x10%5E%7B18%7D)
![N_2(g) + 2O_2(g) \leftrightarrow 2NO_2(g);Kp_3=(8.4x10^{-7})^2=7.056x10^{-13}](https://tex.z-dn.net/?f=N_2%28g%29%20%2B%202O_2%28g%29%20%5Cleftrightarrow%202NO_2%28g%29%3BKp_3%3D%288.4x10%5E%7B-7%7D%29%5E2%3D7.056x10%5E%7B-13%7D)
Subsequently, to obtain the main reaction, we add the aforementioned reference rearranged reactions as shown below (just as reference):
![2NO(g)+N_2(g)+2O_2\leftrightarrow 2NO_2(g)+N_2+O_2](https://tex.z-dn.net/?f=2NO%28g%29%2BN_2%28g%29%2B2O_2%5Cleftrightarrow%202NO_2%28g%29%2BN_2%2BO_2)
Consequently, the equilibrium constant is computed as:
![Kp=\frac{[N_2][O_2]}{[NO]^2} * \frac{[NO_2]^2}{[N_2][O_2]^2} =Kp_2*Kp_3=4.35x10^{18}*7.056x10^{-13}=3.07x10^6](https://tex.z-dn.net/?f=Kp%3D%5Cfrac%7B%5BN_2%5D%5BO_2%5D%7D%7B%5BNO%5D%5E2%7D%20%2A%20%5Cfrac%7B%5BNO_2%5D%5E2%7D%7B%5BN_2%5D%5BO_2%5D%5E2%7D%20%3DKp_2%2AKp_3%3D4.35x10%5E%7B18%7D%2A7.056x10%5E%7B-13%7D%3D3.07x10%5E6)
Best regards.
The H+ concentration in the lake has increased as a result of the acid rain.
The original pH of the lake was 7, which mean the water is neutral, but due to the acid rain, it drops to 5. This means, that the water has become acidic and how have more hydrogen ion. The H+ concentration in the lake has 100 times compares with its original pH.
Ions are stable atoms of elements formed when original atoms loose or gain electrons to form stable configuration. Anions are negatively charged ions formed when atoms gain electrons while cations are the positively charged ions formed when atoms loose electrons. In this case a charge of +1 means an atom lost one electron to form a stable configuration. Therefore, the correct answer is A