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lawyer [7]
2 years ago
15

Help me solve this please (-64)^2/3

Mathematics
2 answers:
Keith_Richards [23]2 years ago
8 0

Answer:

The answer is approximately 42.67

Step-by-step explanation:

64/1 * 2/3 = 128/3

128/3 = about 42.67

I hope this helps!

11Alexandr11 [23.1K]2 years ago
3 0

(-2^6)^(2/3) = -2^(6*2/3) = -2^(4) = -16

Shouldn't be an imaginary number though.

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The figure in Quadrant III of the coordinate plane below is a transformation of the figure in quadrant II.
BARSIC [14]

Answer: 2nd option, 3rd option, and the last option are all correct

5 0
3 years ago
Find the cotangent of angle B. <br> 1. 12/5<br> 2. 12/13<br> 3. 13/12<br> 4. 5/12
labwork [276]
Cot = Cos/Sin

Cos = 12/13
Sin = 5/13

Therefore, 12/3 divided by 5/13 equals 12/5

Answer is 1.

3 0
3 years ago
Read 2 more answers
rachel owns a cupcake shop. last week she used 42.5 pounds of sugar making cupcakes. this week she used 26 pounds of sugar. find
Paha777 [63]

Answer:

decreased by 39%

Step-by-step explanation:

deacreased by

42.5-26= 16.5

16.5÷42.5=38.82352941

rounded to 39%

3 0
3 years ago
Type the correct answer in the box. Round your answer to the nearest integer.
umka21 [38]

Answer:

m∠ADC = 132°

Step-by-step explanation:

From the figure attached,

By applying sine rule in ΔABD,

\frac{\text{sin}(\angle ABD)}{\text{AD}}=\frac{\text{sin}(\angle ADB)}{AB}

\frac{\text{sin}(120)}{35}=\frac{\text{sin}(\angle ADB)}{30}

sin(∠ADB) = \frac{30\text{sin}(120)}{35}

                 = 0.74231

m∠ADB = \text{sin}^{-1}(0.74231)

             = 47.92°

             ≈ 48°

m∠ADC + m∠ADB = 180° [Linear pair of angles]

m∠ADC + 48° = 180°

m∠ADC = 180° - 48°

m∠ADC = 132°

4 0
3 years ago
A sports teacher had 1025 sweets. After distributing these equally amongst all the participants in a sports meet, he had just 1
Cerrena [4.2K]

Step-by-step explanation:

Since it remains only 1 sweet, we can subtract it from the total and get the amount of sweets distributed (=1024).

As all the sweets are distributed equally, we must divide the number of distributed sweets by all its dividers (excluding 1024 and 1, we'll see later why):

1) 512 => 2 partecipants

2) 256 => 4 partecipants

3) 128 => 8 partecipants

4) 64 => 16 partecipants

5) 32 => 32 partecipants

6) 16 => 64 partecipants

7) 8 => 128 partecipants

9) 4 => 256 partecipants

10) 2 => 512 partecipants

The number on the left represents the number of sweets given to the partecipants, and on the right we have the number of the partecipants. Note that all the numbers on the left are dividers of 1024.

Why excluding 1 and 1024? Because the problem tells us that there remains 1 sweet. If there was 1 sweet for every partecipant, the number of partecipants would be 1025, but that's not possible as there remains 1 sweet. If it was 1024, it wouldn't work as well because the sweets are 1025 and if 1 is not distributed it goes again against the problem that says all sweets are equally distributed.

5 0
2 years ago
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