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3 years ago

Which direction do electrons move in when metals react with non-metals?

Chemistry

2 answers:

jek_recluse [69]3 years ago

6 0

Electrons flow metal to nonmetal. That's the answer you're welcome

Varvara68 [4.7K]3 years ago

5 0

Electrons flow from metal to nonmetal.

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Hydrogen fluoride is used in the manufacture of Freons (which destroy ozone in the stratosphere) and in the production of alumin

Lerok [7]

<u>Answer:</u> The percentage yield of HF is 73.36 %

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For calcium fluoride:

Given mass of calcium fluoride = 6.25 kg = 6250 g (Conversion factor: 1 kg = 1000 g)

Molar mass of calcium fluoride = 78.07 g/mol

Putting values in above equation, we get:

$\text{Moles of calcium fluoride}=\frac{6250g}{78.07g/mol}=80.05mol$

For the given chemical reaction:

$CaF_2+H_2SO_4\rightarrow CaSO_4+2HF$

By Stoichiometry of the reaction:

1 mole of calcium fluoride produces 2 moles of hydrofluoric acid

So, 80.05 moles of calcium fluoride will produce = $\frac{2}{1}\times 80.05=160.1mol$ of hydrofluoric acid

Now, calculating the theoretical yield of hydrofluoric acid using equation 1, we get:

Moles of of hydrofluoric acid = 160.1 moles

Molar mass of hydrofluoric acid = 20.01 g/mol

Putting values in equation 1, we get:

$160.1mol=\frac{\text{Theoretical yield of hydrofluoric acid}}{20.01g/mol}=3203.6g=3.20kg$

To calculate the percentage yield of hydrofluoric acid, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of hydrofluoric acid = 2.35 kg

Theoretical yield of hydrofluoric acid = 3.20 kg

Putting values in above equation, we get:

$\%\text{ yield of hydrofluoric acid}=\frac{2.35g}{3.20g}\times 100\\\\\% \text{yield of hydrofluoric acid}=73.36\%$

Hence, the percentage yield of HF is 73.36 %

4 0

3 years ago

The element whose atomic number is 13 has how many valence electrons electron configuration

RideAnS [48]

It is in Group 3A = 3 valence electrons

Electron Config. = 1s2 2s2 2p6 3s2 3p1

4 0

3 years ago

A patients blood is tested for growth hormone which has a molecular mass of 848.952g/mol. The test results show a normal concent

rusak2 [61]

Answer:

$\boxed{4.7\times 10^{-9}}$

Explanation:

Data:

MM = 848.952 g/mol

c = 4.0 x 10⁻⁶ g/L

V = 1 L

Calculations:

(a) Mass of growth hormone

$\text{Mass} = \text{1 L} \times \dfrac{4.0 \times 10^{-6} \text{ g}}{\text{1 L}} = 4.0 \times 10^{-6} \text{ g}$

(b) Moles of growth hormone

$\text{Moles} = 4.0 \times 10^{-6} \text{ g} \times \dfrac{\text{1 mol}}{\text{848.952 g}} = 4.7\times 10^{-9}\text{ mol}\\\\\text{There are $\boxed{\mathbf{4.7\times 10^{-9}}\textbf{ mol}}$ of growth hormone in 1 L of blood.}$

8 0

4 years ago

A sample of gas contains 0.1100 mol of HBr(g) and 5.00x10^-2 mol of Cl2(g) and occupies a volume of 5.85 L. The following reacti

Vesna [10]

The volume of the sample after the reaction : V₂=5.484 L

<h3>Further explanation</h3>

Given

Reaction

2HBr(g) + Cl2(g) => 2HCl (g)+Br2(g)

0.1100 mol of HBr(g)

5x10⁻² mol of Cl2(g)

Required

The volume of the sample after reaction

Solution

Find limiting reactant :

0.11/2 : 0.05/1 = 0.055 : 0.05

Limiting reactant : Cl₂

mol Products based on mol Cl₂

mol products = mol HCl + mol Br₂

mol products = 2/1x0.05 + 1/1x0.05

mol products = 3 x 0.05 = 0.15

mol reactants = 0.11 + 0.05 = 0.16

<em>From Avogadro's law, </em>

In the same T, P, and V, the gas contains the same number of molecules

So the ratio of gas volume will be equal to the ratio of gas moles

V₁/n₁=V₂/n₂

1 = reactants, 2 = products

Input the value :

5.85/0.16=V₂/0.15

V₂=5.484 L

6 0

3 years ago

PLEASE HELP ME ANSWER

Delvig [45]

Answer:

570

Explanation:

a centigram is a gram times 100

So you do 5.7 times 10 and you get 570

7 0

3 years ago