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Marysya12 [62]
4 years ago
13

A patients blood is tested for growth hormone which has a molecular mass of 848.952g/mol. The test results show a normal concent

ration of 4.0 x 10^-6 g/L. How many miles of growth hormone are in 1 L of blood?
Chemistry
1 answer:
rusak2 [61]4 years ago
8 0

Answer:

\boxed{4.7\times 10^{-9}}

Explanation:

Data:

MM = 848.952 g/mol  

   c = 4.0 x 10⁻⁶ g/L

  V = 1 L

Calculations:

(a) Mass of growth hormone

\text{Mass} = \text{1 L} \times \dfrac{4.0 \times 10^{-6} \text{ g}}{\text{1 L}} = 4.0 \times 10^{-6} \text{ g}

(b) Moles of growth hormone

\text{Moles} = 4.0 \times 10^{-6} \text{ g} \times \dfrac{\text{1 mol}}{\text{848.952 g}} = 4.7\times 10^{-9}\text{ mol}\\\\\text{There are $\boxed{\mathbf{4.7\times 10^{-9}}\textbf{ mol}}$ of growth hormone in 1 L of blood.}

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Answer:

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Explanation:

4 0
3 years ago
What mass of N2O5 will result from the reaction of 6.0 mol of NO2 if there is a 61.1% yield in the reaction
Nata [24]

Answer:

2.0 × 10² g

Explanation:

Step 1: Write the balanced equation

2 NO₂ + 0.5 O₂ ⇒ N₂O₅

Step 2: Calculate the theoretical yield, in moles, of N₂O₅

The molar ratio of NO₂ to N₂O₅ is 2:1.

6.0 mol NO₂ × 1 mol N₂O₅/2 mol NO₂ = 3.0 mol N₂O₅

Step 3: Calculate the theoretical yield, in grams, of N₂O₅

The molar mass of N₂O₅ is 108.01 g/mol.

3.0 mol × 108.01 g/mol = 3.2 × 10² g

Step 4: Calculate the real yield, in grams, of N₂O₅

real yield = theoretical yield × percent yield

real yield = 3.2 × 10² g × 61.1% = 2.0 × 10² g

6 0
3 years ago
How does the presence of hcl affect the charges on the complexes?
FrozenT [24]

Hydrochloric Acid (HCl) is a strong acid when it is present in the concentrated form but when it is dissolved in water (H_2O) the atoms of this compound dissociates into its respective ions as shown below:

HCl(aq.) + H_2O(aq.) \rightarrow H_3O^+(aq.) + Cl^-(aq.)

When we add HCl to any complex in its concentrated form the complex does not react at all but when its diluted to 6M and is kept for many hours, the complex reacts slowly. For eg:

[Co(NH_3)_6]^3^+(aq.) + HCl(aq.) \rightarrow  [Co(NH_3)_5Cl]^2^+(aq.) + NH_4^+ (aq.)

As seen from the above reaction it can be seen the positive charge on the complex is reduced by 1 unit because one Cl^- ion gets attached to the centre metal atom, therefore we can conclude that the charge on complex gets reduced by 1 unit when HCl reacts with the complex.

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3 years ago
Why don’t scientists use the Bohr model above to explain charge transfer?
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Answer:

nsksbsjensnsjeiejensbsksks

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3 years ago
Use the bond energy to calculate an approximate value of ΔH for the following reaction. Which is the more stable form of FNO2?
Phoenix [80]

The Lewis structures in which there are no formal charges is the most stable. Hence, structure (b) is the  more stable form of FNO2.

<h3>Lewis structure</h3>

The question is incomplete but I will try to answer you as much as I can. Now the equation is missing hence we can't numerically caculate the enthalpy chnage of the reaction from bond energies. However, we can do this using the formula; Σbond energy of reactants - bond energy of products.

Concerning the Lewis structures of FNO2, the most stable structure is structure (b) as shown in the image attached where the atoms have no formal charges.

Learn more about Lewis structure:brainly.com/question/4144781

8 0
3 years ago
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