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Marysya12 [62]
3 years ago
13

A patients blood is tested for growth hormone which has a molecular mass of 848.952g/mol. The test results show a normal concent

ration of 4.0 x 10^-6 g/L. How many miles of growth hormone are in 1 L of blood?
Chemistry
1 answer:
rusak2 [61]3 years ago
8 0

Answer:

\boxed{4.7\times 10^{-9}}

Explanation:

Data:

MM = 848.952 g/mol  

   c = 4.0 x 10⁻⁶ g/L

  V = 1 L

Calculations:

(a) Mass of growth hormone

\text{Mass} = \text{1 L} \times \dfrac{4.0 \times 10^{-6} \text{ g}}{\text{1 L}} = 4.0 \times 10^{-6} \text{ g}

(b) Moles of growth hormone

\text{Moles} = 4.0 \times 10^{-6} \text{ g} \times \dfrac{\text{1 mol}}{\text{848.952 g}} = 4.7\times 10^{-9}\text{ mol}\\\\\text{There are $\boxed{\mathbf{4.7\times 10^{-9}}\textbf{ mol}}$ of growth hormone in 1 L of blood.}

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Trigonal planars have a 180 degree bond angle but do bent trigonal planars also have a 180 degree bond angle? Thank you ^^
Yanka [14]

Answer:


The ideal bond angle is 120°, but the real bond angle of bent molecules is usually a few degrees less.


Explanation:


The bonds of a trigonal planar AX₃ molecule point toward the corners of an equilateral triangle.


They trisect a circle into three angles of 120° each.


An example is BF₃ (Figure 1). It is perfectly symmetrical, so the F-B-F bond angles are exactly 120°.


===============


Now, consider ozone (Figure 2).


The two O-O bonds are equivalent because of resonance.


There are two bonding groups and a lone pair, for a total of three electron groups.


The electron geometry is trigonal planar, and the molecular shape is bent.


However, the lone pair occupies more space than the bonding electrons.


It repels the bolding electrons, so the O-O-O bond angle is 116°, slightly less than the ideal angle of 120°.


8 0
3 years ago
Read 2 more answers
Use you observation to determine which polymorph is in the customer’s returned chocolate sample.
Butoxors [25]

Answer:

Cocoa butter, the fat in chocolate, can crystallize in any one of 6 different forms (polymorphs, as they are called). Unfortunately, only one of these, the beta crystal (or Form V), hardens into the firm, shiny chocolate that cooks want. Form VI is also a stable hard crystal, but only small amounts of it form from the good beta (Form V) crystals upon lengthy standing. When you buy commercial chocolate it is in the form of beta crystals.

When you melt chocolate and get it above 94° F, you melt these much desired beta crystals and other types of crystals can set up. If you simply let melted chocolate cool, it will set up in a dull, soft, splotchy, disgusting-looking form. Even the taste is different. Fine chocolate has a snap when you break it and a totally different mouthfeel from the other cocoa butter forms.

6 0
2 years ago
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) An organic chemistry lab book gives the following solubility data for oxalic acid 9.5g/100ml water 23.7g/100ml ethanol 16.9g/1
mart [117]

Answer:

Ethanol

Explanation:

Solvent extraction is the process in which a compound transfers from one solvent to another owing to the difference in solubility or distribution coefficient between these two solvents(Science Direct).

We have to remember that oxalic acid will be extracted better into a solvent in which it is more soluble. From the data given; oxalic acid is more soluble in ethanol than in ether.

This simply means that ethanol is a better solvent for extracting oxalic acid  from water when compared to ether.

5 0
3 years ago
Scoring Scheme: 3-3-2-1 Use one of your experimentally determined values of k, the activation energy you determined, and the Arr
Lena [83]

Answer:

K = 2.7x10⁻⁵ at 25ºC

Explanation:

A way to write Arrhenius equation is:

ln K = - Ea/R × (1/T) + lnA

If you graph ln K as Y and 1/T as X (Absolute temperature in K), the equation you will obtain is:

Y = -13815X +35.817

R² = 0.9927

(Taking the last k point as 0.0386) (ln 0.0386), <em>0.1386 has no sense</em>)

Your slope is -13815

-13815K = - Ea/R

-13815K×8.314J/molK = 114858J/mol = Ea

And your intercept =

lnA = 35.817

A = 3.59x10¹⁵

Now, you want to know rate constant at 25ºC = 298.15K. Replacing in the equation (Where Y is ln (activation energy) and X is 1/T):

Y = -13815X +35.817

Y = -13815(1/298.15K) +35.817

Y = -10.5187

lnK = -10.5187

<h3>K = 2.7x10⁻⁵ at 25ºC</h3>

8 0
3 years ago
21. an atom has 216 protons, how many electrons does it have?
yanalaym [24]

Answer:

21: 47 22: 14

Explanation:

4 0
3 years ago
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