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lozanna [386]
3 years ago
5

The image shows sedimentary rock layers with index

Chemistry
1 answer:
vichka [17]3 years ago
5 0

Layer 2 and layer 9 are the same relative age.

Explanation:

The statement that best describes the rock layers is that Layer 2 and layer 9 are the same relative age..

The relative age is used in placing sedimentary rocks in order of their occurrence.

To do this, we apply the sedimentary laws.

The ones applicable here are:

  • Principle of superposition states that in an undisturbed sequence, the oldest layer is at the base and youngest on top.
  • Principle of cross cutting states that a fault and intrusion are younger than the rocks they cut through.
  • Principle of fossil and fauna succession states that fossils and fauna succeed on another in a determinable form.

We see that layers 2 and 9 have the same fossil and are the same lithological units.

learn more:

Sedimentary rocks brainly.com/question/2740663

#learnwithBrainly

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4 0
2 years ago
Balance the following equation:
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Answer: a) 2K_2CrO_4+3Na_2SO_3+10HCl\rightarrow 4KCl+3Na_2SO_4+2CrCl_3+5H_2O

b) 1 mole of SO_2 is produced.

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The skeletal equation is:

K_2CrO_4+Na_2SO_3+HCl\rightarrow KCl+Na_2SO_4+CrCl_3 +H_2O

The balanced equation will be:

2K_2CrO_4+3Na_2SO_3+10HCl\rightarrow 4KCl+3Na_2SO_4+2CrCl_3+5H_2O

Thus the coefficients are 2, 3 , 10 , 4 , 3 , 2 and 5.

b) Oxidation: 2I-^-\rightarrow I_2+2e-^-

Reduction: SO_4^{2-}+2e^-+4H^+\rightarrow SO_2+2H_2O

Net reaction:  2I-^-+SO_4^{2-}+4H^+\rightarrow I_2+SO_2+2H_2O

When 1 mole of I_2 is produced, 1 mole of SO_2 is produced.

8 0
3 years ago
A 0.288 g sample of an unknown monoprotic acid is dissolved in water and titrated with a 0.115 M NaOH solution. After the additi
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Answer:

74.0 g/mol

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Step 1: Write the generic neutralization reaction

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Step 2: Calculate the reacting moles of NaOH

At the equivalence point, 33.83 mL of 0.115 M NaOH react.

0.03383 L × 0.115 mol/L = 3.89 × 10⁻³ mol

Step 3: Calculate the moles of HA that completely react with 3.89 × 10⁻³ moles of NaOH

The molar ratio of HA to NaOH is 1:1. The reacting moles of HA is 1/1 × 3.89 × 10⁻³ mol = 3.89 × 10⁻³ mol.

Step 4: Calculate the molar mass of the acid

3.89 × 10⁻³ moles of HA have a mass of 0.288 g.

M = 0.288 g / 3.89 × 10⁻³ mol = 74.0 g/mol

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