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katrin2010 [14]
3 years ago
13

Terephthalic acid, an important raw material for making Dacron, a synthetic fiber, is made from para-xylene by the following rea

ction: C8H10+3O2 = C8H6O4+2H2O. a) How much terephthalic acid could be made from 204 grams of para-xylene in miles? b) How much could be made in grams?
Chemistry
1 answer:
Vaselesa [24]3 years ago
4 0
The chemical reaction is given as:

<span>C8H10+3O2 = C8H6O4+2H2O

We are given the initial amount of para-xylene for the reaction. We use this amount and the relation of substances from the reaction to obtain the amount of the acid produced.

204 g ( 1 mol / 106.18 g ) ( 1 mol C8H6O4 / 1 mol C8H10 ) ( 166.14 g / mol ) = 319.20 g terephthalic acid</span>
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Latoya performs an experiment using the lab equipment shown. Which two properties is Latoya most likely measuring?
spayn [35]

Answer: Volume and temperature

Explanation:

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3 years ago
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How many grams of NaCl are required to make 150.0 mL of a 5.000 m solution
Oksi-84 [34.3K]

The  grams   of NaCl  that are required  to  make  150.0 ml of  a  5.000 M  solution is  43.875 g


calculation

Step 1:calculate  the  number of moles

moles =  molarity  x volume  in L

volume  = 150 ml / 1000 = 0.15 L

= 0.15 L  x 5.000  M  = 0.75  moles

Step 2:  calculate mass

mass =  moles x  molar mass

molar mass  of NaCl = 23 + 35.5 = 58.5 mol /L


mass is therefore =0.75  moles  x 58.5  mol /l =43.875 g

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3 years ago
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Consider the decomposition of a metal oxide to its elements, where M represents a generic metal. M 3 O 4 ( s ) − ⇀ ↽ − 3 M ( s )
Citrus2011 [14]

Answer:

a) ΔGrxn = 6.7 kJ/mol

b) K = 0.066

c) PO2 = 0.16 atm

Explanation:

a) The reaction is:

M₂O₃ = 2M + 3/2O₂

The expression for Gibbs energy is:

ΔGrxn = ∑Gproducts - ∑Greactants

Where

M₂O₃ = -6.7 kJ/mol

M = 0

O₂ = 0

deltaG_{rxn} =((2*0)+(3/2*0))-(1*(-6.7))=6.7kJ/mol

b) To calculate the constant we have the following expression:

lnK=-\frac{deltaG_{rxn} }{RT}

Where

ΔGrxn = 6.7 kJ/mol = 6700 J/mol

T = 298 K

R = 8.314 J/mol K

lnK=-\frac{6700}{8.314*298} =-2.704\\K=0.066

c) The equilibrium pressure of O₂ over M is:

K=P_{O2} ^{3/2} \\P_{O2}=K^{2/3} =0.066^{2/3} =0.16atm

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3 years ago
A 25 gram(m) metal ball is heated to 200C(delta T) with 2330 Joules(q) of energy. What is the specific heat of the metal?
Dominik [7]

Answer:

The specific heat of the metal is 0.466 \frac{J}{g*C}

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

The equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case:

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Replacing:

2330 J= c*25 g* 200 °C

Solving:

c=\frac{2330 J}{25 g* 200 C}

c=0.466 \frac{J}{g*C}

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