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katrin2010 [14]
3 years ago
13

Terephthalic acid, an important raw material for making Dacron, a synthetic fiber, is made from para-xylene by the following rea

ction: C8H10+3O2 = C8H6O4+2H2O. a) How much terephthalic acid could be made from 204 grams of para-xylene in miles? b) How much could be made in grams?
Chemistry
1 answer:
Vaselesa [24]3 years ago
4 0
The chemical reaction is given as:

<span>C8H10+3O2 = C8H6O4+2H2O

We are given the initial amount of para-xylene for the reaction. We use this amount and the relation of substances from the reaction to obtain the amount of the acid produced.

204 g ( 1 mol / 106.18 g ) ( 1 mol C8H6O4 / 1 mol C8H10 ) ( 166.14 g / mol ) = 319.20 g terephthalic acid</span>
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How to solve for K when given your anode and cathode equations and voltage
Aleks04 [339]

Answer:

See Explanation

Explanation:

In thermodynamics theory the Free Energy (ΔG) of a chemical system is described by the expression ΔG = ΔG° + RTlnQ. When chemical system is at equilibrium ΔG = 0. Substituting into the system expression gives ...

0 = ΔG° + RTlnKc, which rearranges to ΔG° = - RTlnKc.  ΔG° in electrochemical terms gives ΔG° = - nFE°, where n = charge transfer, F = Faraday Constant = 96,500 amp·sec and E° = Standard Reduction Potential of the electrochemical system of interest.

Substituting into the ΔG° expression above gives

-nFE°(cell) = -RTlnKc => E°(cell) = (-RT/-nF)lnKc = (2.303·R·T/n·F)logKc

=> E°(cell) = (0.0592/n)logKc = E°(Reduction) - E°(Oxidation)

Application example:

Calculate the Kc value for a Zinc/Copper electrochemical cell.

Zn° => Zn⁺² + 2e⁻  ;    E°(Zn) = -0.76 volt  

Cu° => Cu⁺² + 2e⁻ ;    E°(Cu) =  0.34 volt

By natural process, charge transfer occurs from the more negative reduction potential to the more positive reduction potential.

That is,

           Zn° => Zn⁺² + 2e⁻ (Oxidation Rxn)

Cu⁺² + 2e⁻ => Cu°             (Reduction Rxn)

E°(Zn/Cu) = (0.0592/n)logKc

= (0.0592/2)logKc = E°(Cu) - E°(Zn) = 0.34v - (-0.76v) = 1.10v

=> logKc = 2(1.10)/0.0592 = 37.2

=> Kc = 10³⁷°² = 1.45 x 10³⁷

3 0
3 years ago
What is the density of 53.4 wt aqueous naoh?
zhenek [66]

Missing question: what is the density of 53.4 wt% aqueous NaOH if 16.7 mL of the solution diluted to 2.00L gives 0.169 M NaOH?

Answer is: density is 1.52 g/mL.

c₁(NaOH) = ?; molarity of concentrated sodium hydroxide.

V₁(NaOH) = 16.7 mL; volume of concentrated sodium hydroxide.

c₂(NaOH) = 0.169 M; molarity of diluted sodium hydroxide.

V₂(NaOH) = 2.00 L · 1000 mL/L = 2000 mL; volume of diluted sodium hydroxide.  

Use equation: c₁V₁  = c₂V₂.

c₁ = c₂V₂ / V₁.

c₁ = 0.169 M · 2000 mL / 16.7 mL.

c₁(NaOH) = 20.23 M.

m(NaOH) = 20.23 mol · 40 g/ml.

m(NaOH) = 809.53 g.

The mass fraction is the ratio of one substance (in this example sodium hydroxide) with mass to the mass of the total mixture (solution).

Make proportion: m(NaOH) : m(solution) = 53.4 g : 100 g.

m(solution) = 1516 g in one liter of solution.

d(solution) = 1516 g/L = 1.52 g/mL.

4 0
3 years ago
What coefficient would the O 2 have after balancing C 4 H 10 +O 2 CO 2 +H 2 O ?
trapecia [35]

Answer:6.5

Explanation:

6 0
3 years ago
Read 2 more answers
Distillation is a _____________ separation technique.
Annette [7]

Answer:

physical

Explanation:

5 0
3 years ago
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Calculate the density of a solid that has a volume of 2cm3 and a mass of 3g
katrin2010 [14]

Answer:

The density is 6

Explanation:

p = m × v

p = 3 × 2

p = 6

Hope this helped! :)

8 0
3 years ago
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