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Delvig [45]
3 years ago
14

Out of 30 questions Ahmad answers 12 of them incorrectly.what percent of the questions did he correctly

Mathematics
2 answers:
Dimas [21]3 years ago
8 0
40% 40/100 .4 divide 14 by 30
12345 [234]3 years ago
5 0
(12/30)x100 is 40%
This is percent of incorrect answers. The total percent must be 100% so subtract 100-40=60%.
60% answers were answered correctly.
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Solve (x-3)^2=5 plssss <br> thxs
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Answer:

=3±√5

Step-by-step explanation:

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Jordan and Sam are putting their money together to buy lunch. Jordan has $5.75 and Sam has $6.25. Jordan wants to order 1 hambur
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Please brake down why !
lana66690 [7]

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D

Step-by-step explanation:

using the rule of radicals

• \sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

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4 0
3 years ago
Find the greatest number which divides 6168, 2447 and 3118 leaving the same remainder in each case.
SSSSS [86.1K]

let the greatest number be a and remainder be x. And let the whole number result of the division be b, c and d. So we have

ab + x = 2447............(1)

ac + x = 3118...............(2)

ad + x = 6168.............(3)

Subtracting (2) - (1) gives:-

ac - ab = 671

a(c - b) =671

Now 671 = 61 * 11 so 61 could be the value of a

Checking:- 2447 / 61 = 40 remainder 7 , 3118 / 61 = 51 remainder 7

and 6168 / 61 = 101 remainder 7

Answer 61

5 0
3 years ago
What is x+4/5=2/3- x-3/6
natima [27]
x+\frac{4}{5}=\frac{2}{3}-x-\frac{\not3^1}{\not6_2}\\\\x+\frac{4}{5}=\frac{2}{3}-x-\frac{1}{2}\\\\find\ LCD(\frac{4}{5};\ \frac{2}{3};\ \frac{1}{2})=2\times3\times5=30\\\\multiply\ both\ sides\ by\ LCD=30\\\\30x+30\cdot\frac{4}{5}=30\cdot\frac{2}{3}-30x-30\cdot\frac{1}{2}\\\\30x+6\cdot4=10\cdot2-30x-15\cdot1\\\\30x+24=20-30x-15

30x+24=5-30x\ \ \ \ |subtract\ 24\ from\ both\ sides\\\\30x=-19-30x\ \ \ \ \ |add\ 30x\ to\ both\ sides\\\\60x=-19\ \ \ \ \ |divide\ both\ sides\ by\ 60\\\\\boxed{x=-\frac{19}{60}}



\frac{x+4}{5}=\frac{2}{3}-\frac{x-3}{6}\\\\\frac{x+4}{5}=\frac{2\cdot2}{3\cdot2}-\frac{x-3}{6}\\\\\frac{x+4}{5}=\frac{4}{6}-\frac{x-3}{6}\\\\\frac{x+4}{5}=\frac{4-(x-3)}{6}\\\\\frac{x+4}{5}=\frac{4-x+3}{6}\\\\\frac{x+4}{5}=\frac{7-x}{6}\ \ \ \ |cross\ multiply

6(x+4)=5(7-x)\\\\6(x)+6(4)=5(7)-5(x)\\\\6x+24=35-5x\ \ \ \ \ |subtract\ 24\ from\ both\ sides\\\\6x=11-5x\ \ \ \ \ |add\ 5x\ to\ both\ sides\\\\11x=11\ \ \ \ \ |divide\ both\ sides\ by\ 11\\\\\boxed{x=1}
6 0
3 years ago
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