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3 years ago

Find the area of the lighter shaded region

Mathematics

1 answer:

vesna_86 [32]3 years ago

7 0

Answer: need picture wont really do good for me

Step-by-step explanation:

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Is this standard form <br>25x - 80y = 160

kvv77 [185]

Answer:

true

Step-by-step explanation:

because the variable terms are in the left side of the equation and everything else in right side.

5 0

3 years ago

How would you eliminate the

Nimfa-mama [501]

Answer:

Multiply each term by LCM of 3 and 4 which is 12

Step-by-step explanation:

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3 years ago

Marty collects colorful paper clips. Each week he is sure to add exactly five new paper clips to his collection. Make a table re

ruslelena [56]

Answer:

all of them

Step-by-step explanation:

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3 years ago

Jesse has a storage container in the shape of a right rectangular prism. The volume of the container is 43.875 cubic meters, the

Gnom [1K]

Answer:

The height is 2.25 meters.

Step-by-step explanation:

The volume of a right rectangular prism is the product of the length, width, and height. So it would be V=w*l*h.

Because you have been given the values of the volume, width, and length, you can plug in those values into the equation to find the height. It should look like this: 43.875=5 * 3.9 * h

Then you can divide both sides of the equation by 5 * 3.9.

So... 43.875/(5*3.9)=h

therefore h= 2.25.

hope this explanation makes sense!

4 0

3 years ago

Read 2 more answers

A film distribution manager calculates that 4% of the films released are flops. If the manager is correct, what is the probabili

Anit [1.1K]

Answer:

9.34%

Step-by-step explanation:

p = 4%, or 0.04

n = Sample size = 667

u = Expected value = n * p = 667 * 0.04 = 26.68

SD = Standard deviation = $\sqrt{np(1-p)} =\sqrt{667*0.04*(1-0.04)}$ = 5.06

Now, the question is if the manager is correct, what is the probability that the proportion of flops in a sample of 667 released films would be greater than 5%?

This statement implies that the p-vlaue of Z when X = 5% * 667 = 33.35

Since,

Z = (X - u) / SD

We have;

Z = (33.35 - 26.68) / 5.06

Z = 1.32

From the Z-table, the p-value of 1.32 is 0.9066

1 - 0.9066 = 0.0934, or 9.34%

Therefore, the probability that the proportion of flops in a sample of 667 released films would be greater than 5% is 9.34%.

6 0

3 years ago