Answers:
Blank 1 = p and r
Blank 2 = corresponding angles converse
==========================================================
Explanation:
Refer to the diagram below. I've marked lines p and r in red, and the angles 3 and 22 in blue. They are corresponding angles because they are both in the same southeast corner of their four-corner configuration.
If the corresponding angles are congruent, then the lines p and r are parallel by the aptly named corresponding angles converse
Answer:
Transitive property of equality is not a justification for the proof.
Step-by-step explanation:
We draw a right angle ΔACB. CD is perpendicular to AB.
Let AC = a , BC = b , AB = c and CD = h
Now in ΔABC and ΔACD
∠C = ∠D and ∠A = ∠A
from AA similarity postulate
ΔABC similar to ΔACD.
Hence,
=
= c × x ·····················(1)
Now in ΔABC and ΔCBD
∠C = ∠D and ∠B = ∠B
from AA similarity postulates
ΔABC similar to ΔCBD
Hence,
= c × y······················(2)
Add equation (1) and (2)
+
= cx + cy
+
= c(x+y)
+
=
[because x+y=c]
Transitive property is not useful for this proof.
