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3 years ago

8

What factors affect the speed of a wave? Check all that apply. the amplitude of the wave the energy of the wave the temperature

of the medium the type of wave the type of medium

1 answer:

Lena [83]3 years ago

4 0

Answer:

I believe its 1,2, and 5

Explanation:

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Which of the following is not a pseudoscientific claim

marshall27 [118]

What are the options?

4 0

3 years ago

You need 1.2 moles of H2SO4 for an experiment. You weigh out 100g of this colorless syrupy liquid. Do you have enough?

Sladkaya [172]

Answer is: not enough <span>colorless syrupy liquid.
</span>n(H₂SO₄) = 1,2 mol.
M(H₂SO₄) = 2Ar(H) + Ar(S) + 4Ar(O) · g/mol.
M(H₂SO₄) = 2·1 + 32 + 4·16 · g/mol.
M(H₂SO₄) = 98 g/mol.
m(H₂SO₄) = n(H₂SO₄) · M(H₂SO₄).
m(H₂SO₄) = 1,2 mol · 98 g/mol.
m(H₂SO₄) = 117,6 g needed.
100 g is less that 117,6 g.

8 0

3 years ago

Determine the volume, in liters, occupied by 0.015 molecules of oxygen at STp?

Arlecino [84]

5.58 X $10^{-25}$ Litres is the volume, in liters, occupied by 0.015 molecules of oxygen at STP.

Explanation:

Data given:

molecules of oxygen = 0.015

number of moles of oxygen =?

temperature at STP = 273 K

Pressure at STP = 1 atm

volume = ?

R (gas constant) = 0.08201 L atm/mole K

to convert molecules to moles,

number of moles = $\frac{molecules}{Avagadro's number}$

number of moles = 2.49 x $10^{-26}$

Applying the ideal gas law since the oxygen is at STP,

PV = nRT

rearranging the equation:

V = $\frac{nRT}{P}$

putting the values in the rearranged equation:

V = $\frac{2.49 X10^{-26} X 0.08201 X 273}{1}$

V = 5.58 X $10^{-25}$ Litres.

5 0

3 years ago

Help! 7th Grade Math!

vagabundo [1.1K]

Answer:

D

Explanation: Trust me

6 0

3 years ago

What is the longest wavelength in the Balmer series? (Hint: the Rydberg constant for Hydrogen is 1.096776×107 1/m, and the Balme

boyakko [2]

<u>Answer:</u> The longest wavelength of light is 656.5 nm

<u>Explanation:</u>

For the longest wavelength, the transition should be from n to n+1, where: n = lower energy level

To calculate the wavelength of light, we use Rydberg's Equation:

$\frac{1}{\lambda}=R_H\left(\frac{1}{n_i^2}-\frac{1}{n_f^2} \right )$

Where,

$\lambda$ = Wavelength of radiation

$R_H$ = Rydberg's Constant = $1.096776\times 10^7m^{-1}$

$n_f$ = Higher energy level = $n_i+1=(2+1)=3$

$n_i$ = Lower energy level = 2 (Balmer series)

Putting the values in above equation, we get:

$\frac{1}{\lambda }=1.096776\times 10^7m^{-1}\left(\frac{1}{2^2}-\frac{1}{3^2} \right )\\\\\lambda =\frac{1}{1.5233\times 10^6m^{-1}}=6.565\times 10^{-7}m$

Converting this into nanometers, we use the conversion factor:

$1m=10^9nm$

So, $6.565\times 10^{-7}m\times (\frac{10^9nm}{1m})=656.5nm$

Hence, the longest wavelength of light is 656.5 nm

4 0

3 years ago