Because after ehough acid rain/Rain it turned turquoise like if you bring a fake gold ring to a pool it will turn brown!
Explanation:
Boiling is defined as a process in which vapor pressure of a liquid substance becomes equal to the atmospheric pressure.
During this change liquid and vapors remain in equilibrium and the equation for this change is as follows.
![X(l) \rightleftharpoons X(g)](https://tex.z-dn.net/?f=X%28l%29%20%5Crightleftharpoons%20X%28g%29)
Therefore, when boiling takes place then average kinetic energy of particles in liquid phase equals to the average kinetic energy of particles in vapor phase.
Hence, we can increase the kinetic energy of particles in liquid phase by increasing the temperature because kinetic energy is directly proportional to temperature as follows.
K.E = ![\frac{3}{2}kT](https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B2%7DkT)
y’all i have this same question someone please help
Answer:
![\boxed{\text{1.81 da}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Ctext%7B1.81%20da%7D%7D)
Explanation:
1. Calculate the decay constant
The integrated rate law for radioactive decay is 1
![\ln\dfrac{A_{0}}{A_{t}} = kt](https://tex.z-dn.net/?f=%5Cln%5Cdfrac%7BA_%7B0%7D%7D%7BA_%7Bt%7D%7D%20%3D%20kt)
where
A₀ and A_t are the counts at t = 0 and t
k is the radioactive decay constant
![\ln \dfrac{846}{269} = k \times 3.00\\\\\ln3.145 = 3.00k\\1.146 = 3.00k\\\\k =\dfrac{1.146}{3}\\\\k = \text{0.382 /da}\\](https://tex.z-dn.net/?f=%5Cln%20%5Cdfrac%7B846%7D%7B269%7D%20%3D%20k%20%5Ctimes%203.00%5C%5C%5C%5C%5Cln3.145%20%3D%203.00k%5C%5C1.146%20%3D%203.00k%5C%5C%5C%5Ck%20%3D%5Cdfrac%7B1.146%7D%7B3%7D%5C%5C%5C%5Ck%20%3D%20%5Ctext%7B0.382%20%2Fda%7D%5C%5C)
2. Calculate the half-life
![t_{\frac{1}{2}} = \dfrac{\ln2}{k} = \dfrac{\ln2}{0.382} = \text{1.81 da}](https://tex.z-dn.net/?f=t_%7B%5Cfrac%7B1%7D%7B2%7D%7D%20%3D%20%5Cdfrac%7B%5Cln2%7D%7Bk%7D%20%3D%20%5Cdfrac%7B%5Cln2%7D%7B0.382%7D%20%3D%20%5Ctext%7B1.81%20da%7D)
The half-life for decay is
.