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s344n2d4d5 [400]
3 years ago
13

How did convection currents cause the plates to move

Chemistry
1 answer:
Paul [167]3 years ago
4 0
Convection currents in the mantle are powered by the heat from the earth's core. The convection cells move in a circular motion in the mantle as the plumes or currents of magma rises and falls due to heating and cooling. This circular motion will affect the base of the crust and drag the crustal plates along. The movement however is very slow, as plates only move a few centimeters or inches per year. 
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In a student experiment, the empirical formula of a copper halide was found by adding aluminum metal to an aqueous solution of t
Radda [10]

<u>Answer:</u> The empirical formula for the given compound is CuCl_3

<u>Explanation:</u>

We are given:

Mass of copper chloride in 1 L or 1000 mL of solution = 42.62 grams

<u>Taking Trial A:</u>

Volume of solution = 49.6 mL

Applying unitary method:

In 1000 mL of solution, the mass of copper chloride present is 42.62 grams

So, in 49.6 mL of solution, the mass of copper chloride will be = \frac{42.62}{1000}\times 49.6=2.114g

We are given:

Mass of filter paper = 0.908 g

Mass of filter paper + copper = 1.694 g

Mass of copper = [1.694 - 0.908] g = 0.786 g

Mass of chlorine in the sample = [2.114 - 0.786]g = 1.328 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Copper =\frac{\text{Given mass of Copper}}{\text{Molar mass of Copper}}=\frac{0.786g}{63.5g/mole}=0.0124moles

Moles of Chlorine = \frac{\text{Given mass of Chlorine}}{\text{Molar mass of Chlorine}}=\frac{1.328g}{35.5g/mole}=0.0374moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.0124 moles.

For Copper = \frac{0.0124}{0.0124}=1

For Chlorine = \frac{0.0374}{0.0124}=3.02\approx 3

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of Cu : Cl = 1 : 3

Hence, the empirical formula for the given compound is CuCl_3

3 0
3 years ago
I PLEASE HELP! How many liters of a 2.25 molar hydrobromic acid (HBr) solution would be needed to react completely with 100.0 gr
PtichkaEL [24]
Moles of calcium metal used = 100/40.1=2.5
Moles of HBr need to react = 5 moles 
As the molar ratio is 1 is to 2 among them 
so
Moles=molarity x volume
5=2.25 x volume
volume=2.22 litres of HBr required for this reaction
ANSWER IS 2.22 LITRES
8 0
3 years ago
The partial pressure of N2 in a mixture of gases, where the total pressure is 1.50 atm, is 300. torr. What is the mole fraction
makvit [3.9K]

Answer:

The mole fraction of N₂ is 0.26.

Explanation:

The pressure exerted by a particular gas in a mixture is known as its partial pressure. So, Dalton's law states that the total pressure of a gas mixture is equal to the sum of the pressures that each gas would exert if it were alone:

PT = PA + PB

This relationship is due to the assumption that there are no attractive forces between the gases.

Dalton's partial pressure law can also be expressed in terms of the mole fraction of the gas in the mixture. The mole fraction is a dimensionless quantity that expresses the ratio of the number of moles of a component to the number of moles of all the components present.

So in a mixture of two or more gases, the partial pressure of gas A can be expressed as:

PA = XA * PT

In this case:

  • PA= PN₂= 300 torr
  • XA=XN₂= ?
  • PT= 1.50 atm= 1140 torr (being 1 atm= 760 torr)

Replacing:

300 torr= XN₂*1140 torr

Solving:

X_{N_{2} } =\frac{300 torr}{1140 torr}

XN₂= 0.26

<u><em>The mole fraction of N₂ is 0.26.</em></u>

6 0
3 years ago
How many molecules of water are there in 0.234 L of water
tankabanditka [31]

Answer:

7.82x10^24 molecules of water

Explanation:

H2O=18.015 g/mol   Avogadro's #=6.022x10^23 molecules

0.234L x 1000g/1L x 1 mol H2O/18.015 g x 6.022x10^23 = 7.82x10^23 molecules of water

3 0
2 years ago
If 20 mL of gas is subjected to a temperature change from 10°C to 100°C and a pressure change from 1 atm to 10 atm,
Evgesh-ka [11]

Answer:

E. None of these

Explanation:

We know, By GAS laws,

PV = NRT, where p- pressure, v- volume, n- number of moles, R- gas constant ,and T- temperature

Now, In the question, the number of moles remains the same as the gas is the same. so n is constant so we can compare n before and after a temperature change.

\frac{P1V1}{RT1} = \frac{P2V2}{RT2}

where P1= 1 atm, P2 = 10 atm, V1= 20 mL, T1= 10°C and T2= 100°C

We don't have to worry about the standard units as they are present equally on both the sides and get cut, same goes for R( gas constant)

So putting values, we get

\frac{1*20}{R*10} = \frac{10*V2}{R*100}

Cutting, R on both sides and moving contents to the right so that only V2 is left on the left.

\frac{1*20*100}{10*10} = V2

∴ V2 = \frac{2000}{100}

∴ V2 = 20mL

3 0
2 years ago
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