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Nookie1986 [14]
3 years ago
7

A disc is thrown through the air for 1.5 min with a power output of 12.5 W. How much work is done when throwing the disc?

Physics
1 answer:
klasskru [66]3 years ago
7 0

Answer:

work = 1125 [J]

Explanation:

To solve this problem we must remember the definition of power, which is defined as the relationship between work and time. The power can be calculated using the following equation:

Power = work/time

Power = 12.5 [w]

work = joules [J]

time = 1.5 [min] = 90 [s]

work = 12.5*90

work = 1125 [J]

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Explanation:

For this case we have this:

Action force: Would be the force of your feet against the Earth given by the weight defined as:

W = mg

Where g is a constat who represent the gravity g =9.8 m/s^2 in Earth

Reaction force: Would be the force of the Earth pushing against your feet. And on this case is represented by the normal force defined as:

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Where \mu represent the friction coefficient between the ground and the object.

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