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Nookie1986 [14]
3 years ago
7

A disc is thrown through the air for 1.5 min with a power output of 12.5 W. How much work is done when throwing the disc?

Physics
1 answer:
klasskru [66]3 years ago
7 0

Answer:

work = 1125 [J]

Explanation:

To solve this problem we must remember the definition of power, which is defined as the relationship between work and time. The power can be calculated using the following equation:

Power = work/time

Power = 12.5 [w]

work = joules [J]

time = 1.5 [min] = 90 [s]

work = 12.5*90

work = 1125 [J]

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Answer:

0.25 m

Explanation:

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All electromagnetic waves travel in a vacuum always at the same speed, the speed of light, whose value is:

c=3.0\cdot 10^8 m/s

Microwave is an example of electromagnetic waves.

The relationship between wavelength and frequency for an electromagnetic wave is:

\lambda=\frac{c}{f}

where

\lambda is the wavelength

c=3.0\cdot 10^8 m/s  is the speed of light

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For the microwave in this problem,

f=1.2\cdot 10^9 Hz

So its wavelength is

\lambda=\frac{3.0\cdot 10^8}{1.2\cdot 10^9}=0.25 m

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TiliK225 [7]

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2 years ago
What are the complementary colors of magenta? Blue? And cyan?
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Explanation:

Given that,

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