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anzhelika [568]
3 years ago
12

A roller coaster starts from rest at its highest point and then descends on its (frictionless) track. its speed is 40 m/s when i

t reaches ground level. part a what was its speed when its height was half that of its starting point? what was its speed when its height was half that of its starting point? 33 m/s 14 m/s 20 m/s 28 m/s
Physics
1 answer:
Alenkinab [10]3 years ago
5 0

Given that,

Initial velocity , Vi = 0

Final velocity , Vf = 40 m/s

Acceleration due to gravity , a = 9.81 m/s²

Distance can be calculated as,

2as = Vf² - Vi²

2 * 9.81 *s = 40² - 0²

s = 81.55 m

For half height, that is, s = 40.77m

Vf= ??

2as = Vf² - Vi²

2 * 9.81 * 40.77 = Vf² - 0²

Vf² = 800

Vf = 28.28 m/s

Therefore, speed of roller coaster when height is half of its starting point will be 28 m/s.  

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Question:
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She can swing 1.0 m high.

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Hi there!

The mechanical energy of Jane (ME) can be calculated by adding her gravitational potential (PE) plus her kinetic energy (KE).

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She can swing 1.0 m high (if we neglect dissipative forces such as air resistance).

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3 years ago
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