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horsena [70]
3 years ago
14

Helpppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppppp

Physics
1 answer:
Lesechka [4]3 years ago
5 0
There’s force of friction/ drag that slows down a moving object, there’s also gravity pulling the wagon down which would help slow it down. Hope this helps good luck.
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Assertion: In electrical circuits the connecting wires are usually made of thick copper wires. Reason: Thicker wires offer highe
julia-pushkina [17]

There actually three assertions here: one in A and two more in B.

All three assertions, as well as the reasoning described in this mess, are all False.

The correct choice from the list is e), but that doesn't even describe the complete Falseness of this disaster.

8 0
3 years ago
A small 21 kilogram canoe is floating downriver at a speed of 1 m/s. What is the canoe's kinetic energy?
tamaranim1 [39]
Kinetic energy is the energy of a moving object.
Kinetic energy can be calculated using the following equation;
K.E = \frac{1}{2} m v^{2}
where - m - mass of object
v - speed of object 
substituting the values in the equation 
K.E = 1/2 x 21 kg x (1 m/s)²
K.E = 10.5 J
8 0
4 years ago
how your weight would change with time if you were on a space ship traveling away from,earth toward the moon
Mkey [24]
U wouldn't get enough vitamins
4 0
4 years ago
Kevin has a mass of 87 kg and is skating with in-line skates. He sees his 22-kg younger brother up ahead standing on the sidewal
neonofarm [45]

Answer:

V_ k = 3 m/s  

Explanation:

Using the conservation of the linear momentum P:

P_i = P_f

so:

M_kV_k = M_sV_s

where M_k is the mass of kevin, V_k is the velocity of kevin before he grabs her brother, M_s is the velocity of her brother and him after grabs her brother and V_s is the velocity of both after the collition.

So, replacing the values and solving for Vk, we get:

(87 kg)V_k = (87 kg+22 kg)(2.4m/s)

V_ k = 3 m/s

8 0
3 years ago
An electron has a kinetic energy of 10.1 eV. The electron is incident upon a rectangular barrier of height 18.2 eV and width 1.0
podryga [215]

Answer:

factor that the electron's probability of tunneling through the barrier increase 2.02029

Explanation:

given data

kinetic energy = 10.1 eV

height = 18.2 eV

width = 1.00 nm

wavelength = 546 nm

solution

we know that probability of tunneling is express as

probability of tunneling = e^{-2CL}   .................1

here C is = \frac{\sqrt{2m(U-E}}{h}

here h is Planck's constant

c = \frac{\sqrt{2\times 9.11 \times 10^{-31} (18.2-10.1) \times (1.60 \times 10^{-19}}}{6.626\times 10^{-34}}  

c = 2319130863.06

and proton have hf = \frac{hc}{\lambda } = {1240}{546} = 2.27 ev

so electron K.E = 10.1 + 2.27

KE = 12.37 eV

so decay coefficient inside barrier is

c' = \frac{\sqrt{2m(U-E}}{h}

c' = \frac{\sqrt{2\times 9.11 \times 10^{-31} (18.2-12.37) \times (1.60 \times 10^{-19}}}{6.626\times 10^{-34}}  

c' = 1967510340

so

the factor of incerease in transmisson probability is

probability = e^{2L(c-c')}

probability = e^{2\times 1\times 10^{-9} \times (351620523.06)}

factor probability = 2.02029

3 0
3 years ago
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