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4 years ago

What is the velocity of an 500-kilogram elevator that has 4,000 joules of energy?

1 answer:

8 0

$E=\frac{mv^2}2 \\ 2E=mv^2 \\ v^2=\frac{2E}m \\ v=\sqrt\frac{2E}m \\ v=\sqrt\frac{8000}{500} \\ v=\sqrt{16} \\ v=4$
4 meters per second.

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What would happen if you touched an object that is the same temperature as your hand? Would any heat transfer happen? Explain yo

ICE Princess25 [194]

Answer:

It actually depends.

Explanation:

in the case of a metal ur hand will absorb the heat (but it depends on the temperature, this ans favours hot and cold but not neutral or room temperature), in the case of human to human I think no heat transfer will take place, in the case of liquids(for hot temperature ,it would even for cold but not room).

It basically involves application

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3 years ago

Consider a air-filled parallel-plate capacitor with plates of length 8 cm, width 5.52 cm, spaced a distance 1.99 cm apart. Now i

prohojiy [21]

Answer:

The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58

Explanation:

Given that,

Length of plates = 8 cm

Width = 5.52 cm

Distance = 1.99 cm

Dielectric constant = 2.6

Length = 4.4 cm

Potential = 0.8 V

We need to calculate the initial capacitance

Using formula of capacitance

$C=\dfrac{\epsilon_{0}A}{d}$

Put the value into the formula

$C=\dfrac{8.85\times10^{-12}\times8\times5.52\times10^{-4}}{1.99\times10^{-2}}$

$C=1.96\times10^{-12}$

We need to calculate the final capacitance

Using formula of capacitance

$C'=\dfrac{\epsilon_{0}A_{1}}{d}+\dfrac{k\epsilon_{0}A_{2}}{d}$

Put the value into the formula

$C'=(\dfrac{8.85\times10^{-12}}{1.99\times10^{-2}})((4.4\times5.52)+(3.6\times5.52)2.6)\times10^{-4}$

$C'=3.37\times10^{-12}$

We need to calculate the ratio of the new potential energy to the potential energy before the insertion of the dielectric

Using formula of energy

$\dfrac{E}{E'}=\dfrac{\dfrac{1}{2}CV^2}{\dfrac{1}{2}C'V^2}$

Put the value into the formula

$\dfrac{E}{E'}=\dfrac{1.96\times10^{-12}}{3.37\times10^{-12}}$

$\dfrac{E}{E'}=0.58$

Hence, The ratio of the new potential energy to the potential energy before the insertion of the dielectric is 0.58

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3 years ago

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Elina [12.6K]

C. Short wavelength

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tester [92]

Hey there, hope you’re having a positive day. Can you try translate this into English please, unfortunately I do not understand your question as I don’t understand your language. No hate towards you happy Thanksgiving

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Zolol [24]

I believe the answer is A.

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3 years ago