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adoni [48]
3 years ago
8

You are given two unknown acids, HX and H2Y, and two values for Ka, 1x10^-7 and 1x10^9. You know that X is a much more electrone

gative atom than Y. Which Ka value goes with which acid? 1. Choice (1) HX has a Ka of 1x10-7 and H2Y has a Ka of 1x10 2. Choice (2) HX has a Ka of 1x109 and H2Y has a Ka of 1x107 Explain your reasoning.
Chemistry
1 answer:
Elena L [17]3 years ago
6 0

Answer:

.

Explanation

In HX , X is more electronegative than Y so HX will ionise more because of  ionic bond between H and X . On the other hand H₂Y will be less polar as compared to HX so it will ionise to a lesser extent . Hence Ka will be more for HX . Ka represents the degree of ionisation of acid . Higher the ionisation , higher is the value of Ka . H₂Y which is less polar will ionise less and hence it will have lesser value of Ka .

Hence H₂Y will have value of 10⁻⁷ and HX will have value of ka equal to 10⁹ .

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Answer:

If we assume the molar volumes of water and ethanol 17.0 and 57.0 cm³/mol, respectively, Vmix = 20.5 cm³.

Explanation:

The molar volume of a substance is the ratio between the volume and the number of moles of the substance. It represents the volume that 1 mol of it occupies. Because we don't have access to page 24, let's assume the molar volumes of water and ethanol 17.0 and 57.0 cm³/mol, respectively.

The volume of mixture (Vmix) is the sum of the volume of each substance, which is the number of moles multiplied by molar volume, so:

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3 years ago
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Elena L [17]
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2 years ago
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What is the density (g / mL) of a substance that has a mass of 8.11 g and, when placed into a graduated cylinder, causes the wat
MAXImum [283]

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<h3>The answer is 0.42 g/mL</h3>

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8 0
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Answer:

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V

i

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3

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∴ΔU=0

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∴q=–w

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i

​

V

f

​

​

)

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