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Brilliant_brown [7]
3 years ago
6

How reactive is an atom of Sodium(Na) and why?

Chemistry
2 answers:
Andreyy893 years ago
8 0
<span>Sodium (Na) is very reactive because it does not have a full valence shell. For any element, the reactivity is related to how full the valance shell is. If it's not full, but is easily made full, it's very reactive. If it's full, it's non reactive. The valance shell can be filled by either removing the electrons from it, or by adding electrons to it, which ever is the lower number of electrons. So with that in mind, let's look at the available choices and see what makes or doesn't make sense. Sodium (Na) is very reactive because it does not have a full valence shell. * This is correct. And because sodium only has 1 electron in its outer shell, it's very reactive since it can lose that electron very easily. This is the correct answer. Sodium (Na) is very reactive because it does not have enough protons in the nucleus. * The number of protons simply tells you what element it is, it doesn't have any effect on its reactivity except indirectly by determining how many electrons the atom has in its neutral state. So this is an incorrect answer. Sodium (Na) is not very reactive because it does not have a full valence shell. * Sodium is most definitely very reactive. If you don't believe that, just toss a chunk of it into the nearest body of water and see what happens. And since this option is claiming that sodium isn't very reactive, it's obviously wrong. Sodium (Na) is not very reactive because it can only bond with Chlorine (Cl) to become salt. * For the same reason that the previous choice was wrong, so is this one wrong.</span>
cricket20 [7]3 years ago
5 0
The correct option is this: SODIUM IS VERY REACTIVE BECAUSE IT DOES NOT HAVE A FULL VALENCE SHELL.
For an atom to attain an octet form, it must have eight electrons in its outermost shell. Elements with eight electrons in their outermost shells are un-reactive. Sodium has only one electron in its outermost shell, this makes it to be very reactive because it is very willing to react with suitable elements in order to become stable.
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Answer:

Explanation:

If we look at the structure of 1-Bromopropane; we will see that it is a derivative of alkane family by the the substitution of an alkyl group. The position of the Bromine in the propane is 1, making 1-Bromopropane  a primary alkyl-halide.

Primary alkyl - halide undergo SN2 mechanism. This nucleophilic reaction needs to be a strong alkyl halide , such as 1-Bromopropane used  otherwise it will result to a reactive mechanism if a weak electrophile is used.

However, the critical and the main objective here is to Draw the major substitution product if the reaction proceeds in good yield. If no reaction is expected or yields will be poor, draw the starting material in the box. If a charged product is formed, be sure to draw the counterion.

The attached diagrams portraying this notions is shown in the attached file below.

5 0
3 years ago
What is the ph of a 4.8 m pyridine solution that has kb = 1.9 × 10-9? the equation for the dissociation of pyridine is?
Eddi Din [679]

Answer: 9.98


Explanation:


1) The equation for the dissociation of pyridine is:


C₅H₅N₅(aq )+ H₂O(l) ⇄ C₅H₅NH⁺(aq) + OH⁻(aq)


2) Kb equation:


Kb = [C₅H₅NH⁺(aq)] [OH⁻(aq)] / [C₅H₅N₅(aq )]


Where:


[C₅H₅NH⁺(aq)] = [OH⁻(aq)] ← from the equilibrium reaction


[C₅H₅N₅(aq )] = 4.8 M ← from the statement


⇒ 1.9 × 10 ⁻⁹ = x² / 4.8 ⇒ x² = 9.12 × 10⁻⁹


⇒ x = 9.55 × 10⁻⁵ = [OH⁻(aq)]


3) pOH


pOH = - log [OH⁻(aq)] = 4.02


4) pOH + pH = 14


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Hope this helps! :)

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