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Brilliant_brown [7]
3 years ago
6

How reactive is an atom of Sodium(Na) and why?

Chemistry
2 answers:
Andreyy893 years ago
8 0
<span>Sodium (Na) is very reactive because it does not have a full valence shell. For any element, the reactivity is related to how full the valance shell is. If it's not full, but is easily made full, it's very reactive. If it's full, it's non reactive. The valance shell can be filled by either removing the electrons from it, or by adding electrons to it, which ever is the lower number of electrons. So with that in mind, let's look at the available choices and see what makes or doesn't make sense. Sodium (Na) is very reactive because it does not have a full valence shell. * This is correct. And because sodium only has 1 electron in its outer shell, it's very reactive since it can lose that electron very easily. This is the correct answer. Sodium (Na) is very reactive because it does not have enough protons in the nucleus. * The number of protons simply tells you what element it is, it doesn't have any effect on its reactivity except indirectly by determining how many electrons the atom has in its neutral state. So this is an incorrect answer. Sodium (Na) is not very reactive because it does not have a full valence shell. * Sodium is most definitely very reactive. If you don't believe that, just toss a chunk of it into the nearest body of water and see what happens. And since this option is claiming that sodium isn't very reactive, it's obviously wrong. Sodium (Na) is not very reactive because it can only bond with Chlorine (Cl) to become salt. * For the same reason that the previous choice was wrong, so is this one wrong.</span>
cricket20 [7]3 years ago
5 0
The correct option is this: SODIUM IS VERY REACTIVE BECAUSE IT DOES NOT HAVE A FULL VALENCE SHELL.
For an atom to attain an octet form, it must have eight electrons in its outermost shell. Elements with eight electrons in their outermost shells are un-reactive. Sodium has only one electron in its outermost shell, this makes it to be very reactive because it is very willing to react with suitable elements in order to become stable.
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PLS HELP ASAP TY. What kind of bond would many atoms of the same metal make?
alexira [117]

Answer:

Metallic bond

Explanation:

7 0
3 years ago
What is the volume of 70.0 g of ether if density os 0.70 g/mL
sdas [7]
D = m / V

0.70 g/mL =  \frac{70.0g}{V}

V =  \frac{m}{D}

V =  \frac{70.0g}{0.70g/mL}

V = 100 mL

hope this helps!

3 0
3 years ago
Estimate the coordination number for the cations in each of these ceramic oxides and also the coordination numbers of the oxygen
Juli2301 [7.4K]

Answer:

CN cation, anion ] respectively are thus [6,4] , [2,3] ,[6,6] , [6,6] , [6,3] , [12,6,2] , [6], [6].

Explanation:

The coordination number CN is the number of ligand atoms bonded (coordinate bonds) directly to the central of the metal ion. It is not the same as the oxidation state of the metal ion or complex.

Coordination number – the number of anions surrounding the cation.

In solving for CN we need to understand Pauling's rules.

According to Linus Pauling, 1932

“Pauling’s rules” for crystal structures, makes assumptions for ionic bonding. It states that ionic structure is understood using electrostatic rules of attraction and repulsion.

Cations and anions surround each other to neutralize charge – and these one can rationalize crystal structure with coordination number.

Ratio of cationic/anionic radius

• The structure of D-Al2O3 results in coordination number of 6 and 4 for cation and anion respectively.

• The average oxygen coordination number in v-B2O3 is equal to the average cation coordination number × cation/anion ratio (2/3).

• Co-ordination number of Ca2+ ion is =6;

In CaO crystal, Ca2+ is a cation and O2- is an anion. Cationic (Ca2+) has radius 100 pm and anionic (O2-) has radius  145 pm.

Ratio of cationic/anionic radius is:

r⁺/r⁻ = 100 / 145

r⁺/r⁻ = 0.69

CaO will form FCC lattice.

Coordination number in FCC lattice is 6. Therefore CN of Ca2+ = 6.

For MgO:

r Mg2+/ r O2- = 86pm / 126 pm =0.683

The cordination number for the cation is 6. MgO with ions Mg+2 and O-2 will have a AX type stochiometry exhibiting the

crystal structure of sodium chloride.

For TiO2:

The CN of the titanium (IV) cation is 6, which is twice the CN of the oxide anion, which is 3.

This fits with the formula unit of TiO2, since there are twice as many O2− ions as Ti4+ ions.

Consequently the crystal structure of all ionic compounds reflects the formula unit.

For LaAlO3 a Cubic perovskites (ABX3)

In perovskite structures, B cations are coordinated by six X anions, while A

cations present CN = 12 (also coordinated by X anions). The X anions have CN = 2, being

coordinated by two A cations, since the distance A-O is about 40% larger than the B-O

bond distance. The correct ionic radii (rA, rB, rX), taken from one of Shannon’s work.

rA = 1.36 pm

rB = 0.535 pm

rX = 1.35 pm

Forsterite Mg2SiO4

We have mixed sites of Si4+ in tetrahedral site, Mg2+ in octahedral site, O atoms anions .

They all forms octahedral chains/strips. The CN is estimated to (6) octahedral, with an average ratio 0.414

Nickel Cobaltite Ni(Co2O4)3

bidentate ligand includes the Oxalate, three oxalate ligands form six-coordinate bonds around the Ni2+ ion.

Co-ordinate number of Nickel in [Ni(C2​O4​)3​] 4− is 3×2=6.

5 0
3 years ago
What’s the answers to these?
nata0808 [166]

Answer:

0bervation

Explanation:

cause it is

5 0
3 years ago
What is the percent composition of Br in CuBr3?
tekilochka [14]

Answer:

about 79% (79.04369332 to be exact)

Explanation:

Percent composition=(Molar mass of element x amount of it)/Molar mass of compound x 100

Br= 3 x 79.9/303.25 x100=79.04369332

6 0
3 years ago
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