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spayn [35]
3 years ago
12

The levels of biological organization for most multicellular organisms

Chemistry
1 answer:
grin007 [14]3 years ago
3 0

The five levels of organization in a multicellular organism are cells, tissues, organs, organ systems and organisms. The level of complexity and functionality increases going from cells to organisms.

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Now molecules:
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Answer:

a

Explanation:

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3 years ago
The periodic table includes all of the known elements in the world. how are elements arranged on the periodic table?
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The elements in a periodic table are arranged in the increasing order of their atomic number. 
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If a 65 kilogram student exerts a force with a magnitude of 100 N on a 100 kilogram desk the magnitude of the force that the des
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C. The action/reaction law states that a force is equal in both directions.
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3 years ago
What volume of 0.235 M H2SO4 is needed to titrate 40.0 mL of 0.0500 M Na2CO M NaCO3 solution?
Andreyy89

Answer: The volume of 0.235 M H_2SO_4 needed to titrate 40.0 mL of 0.0500 M Na_2CO_3 is 8.51 ml

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Na_2CO_3

We are given:

n_1=2\\M_1=0.235M\\V_1=?mL\\n_2=2\\M_2=0.0500M\\V_2=40.0mL

Putting values in above equation, we get:

2\times 0.235\times V_1=2\times 0.0500\times 40.0\\\\V_1=8.51mL

Thus volume of 0.235 M H_2SO_4 needed to titrate 40.0 mL of 0.0500 M Na_2CO_3 is 8.51 ml

5 0
3 years ago
How many grams of zinc chloride could be formed from the reaction of 3.57g of zinc with excess HCl?
lorasvet [3.4K]
MZn: 65 g/mol
mZnCl₂: 65g+35,5g×2 = 136 g/mol
.....................
Zn + 2HCl -----> ZnCl₂ + H₂
65g.......................136g............

65g Zn ---- 136g ZnCl₂
3,57g Zn ---- X
X = (3,57×136)/65
X = 7,47g ZnCl₂
5 0
4 years ago
Read 2 more answers
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