All categories

3 years ago

What is the angle o in the triangle below? (Hint: Use an inverse trigonometric function.)

Physics

1 answer:

Margaret [11]3 years ago

5 0

Answer:

Zero angle is possible geometrically in a right triangle when its length of opposite side is equal to zero. Due to zero length of opposite side, the length of hypotenuse is absolutely equal to the length of hypotenuse.

You might be interested in

Diagnostic ultrasound of frequency 4.50 MHz is used to examine tumors in soft tissue. (a) What is the wavelength in air of such

mafiozo [28]

(a) $7.62 \times 10^{-5} m$ is the wavelength in air of such a sound wave.

(b) $3.33 \times 10^{-4}\ m$ is the wavelength of this wave in tissue.

<u>Explanation:</u>

Frequency and wavelength can be related by the equation,

Velocity = Wavelength x Frequency

$v=\lambda \times f$

where,

v - velocity of light for all EM (electromagnetic) waves in vacuum

Given:

f - 4.50 MHz = $4.50 \times 10^{6} \mathrm{Hz}$

a) To find the wavelength in air

We know,

Speed of sound in air = 343 m/s

Apply given frequency and speed of sound in air, we get

$\lambda=\frac{v}{f}=\frac{343}{4.5 \times 10^{6}}=76.2 \times 10^{-6}=7.62 \times 10^{-5}\ \mathrm{m}$

b) If the speed of sound in tissue is 1500 m/s, find the wavelength of this wave in tissue

Speed of sound in tissue, v = 1500 m/s

$\lambda=\frac{v}{f}=\frac{1500}{4.5 \times 10^{6}}=333.33 \times 10^{-6}=3.33 \times 10^{-4} \mathrm{m}$

4 0

3 years ago

Some unpolarized light has an intensity of 1375 W/m2 before passing through three polarizing filters. The transmission axis of t

chubhunter [2.5K]

Answer:

intensity of the light that emerges from the three filters is 560.80 W/m²

Explanation:

Given data

intensity I = 1375 W/m2

angle 1 = 31.0°

angle 2 = 41.0°

to find out

intensity of the light that emerges from the three filters

solution

we know intensity of light pass 1st polarize = I/2 = 1375 / 2 = 687.5 W/m2

so intensity after 2nd polarize pass = I 1st cos²(θ)

I 2nd = 687.5 cos²(31) = 687.5 ( 0.836754) = 575.27 W/m2

and

intensity after 3rd polarize pass = I 2nd cos²(θ)

I 3rd = 575.27 cos²(41) = 575.27 (0.974839) = 560.80 W/m2

so that intensity of the light that emerges from the three filters is 560.80 W/m²

4 0

4 years ago

Two objects A and B vertically thrown up with velocities 80m/s and 100m/s at two sec interval.where and when will they meet each

romanna [79]

Answer:

hcbvdgsyyvjusvbxjxu usbsbhsi

Explanation:

ysggsghxuxgscsixigdvgsibxhdhshshjf

7 0

3 years ago

How is light generated?

Fudgin [204]

<span>electrons change momentum, some of them slough off photons. And some of those photons have energy in the visible light range of the electro-magnetic spectrum. </span>

5 0

3 years ago

A crate hangs from a ring at the middle of a rope, as the drawing illustrates. a person is pulling on the right end of the rope

aev [14]

Answer:

Explanation:

In order for the rope to be perfectly horizontal, there must be a vertical component in tension

5 0

2 years ago