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weqwewe [10]
3 years ago
11

A fuse in an electric circuit is a wire that is designed to melt, and thereby open the circuit, if the current exceeds a predete

rmined value. Suppose that the material to be used in a fuse melts when the current density rises to 520 A/cm2. What diameter of cylindrical wire should be used to make a fuse that will limit the current to 0.62 A
Physics
1 answer:
arlik [135]3 years ago
3 0

Answer:

0.0389 cm

Explanation:

The current density in a conductive wire is given by

J=\frac{I}{A}

where

I is the current

A is the cross-sectional area of the wire

In this problem, we know that:

- The fuse melts when the current density reaches a value of

J=520 A/cm^2

- The maximum limit of the current in the wire must be

I = 0.62 A

Therefore, we can find the cross-sectional area that the wire should have:

A=\frac{I}{J}=\frac{0.62}{520}=1.19\cdot 10^{-3} cm^2

We know that the cross-sectional area can be written as

A=\pi \frac{d^2}{4}

where d is the diameter of the wire.

Re-arranging the equation, we  find the diameter of the wire:

d=\sqrt{\frac{4A}{\pi}}=\sqrt{\frac{4(1.19\cdot 10^{-3})}{\pi}}=0.0389 cm

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What is a centripetal acceleration of a point on a bicycle wheel of a radius of 0.70 m when a bike is moving 8.0 m/s
Furkat [3]

Answer:

The acceleration of a point on the wheel is 11.43 m/s² acting radially inward.

Explanation:

The centripetal acceleration acts on a body when it is performing a circular motion.

Here, a point on the bicycle is performing circular motion as the rotation of the wheel produces a circular motion.

The centripetal acceleration of a point moving with a velocity v and at a distance of r from the axis of rotation is given as:

a=\frac{v^2}{r}

Here, v=8\ m/s,r=0.70\ m

∴ a=\frac{8}{0.70}=11.43\ m/s^2

Therefore, the acceleration of a point on the wheel is 11.43 m/s² acting radially inward.

3 0
3 years ago
The per-unit impedance of a single-phase electric load is 0.3. The base power is 500 kVA, and the base voltage is 13.8 kV. a. Fi
Leto [7]

Answer:

114.26

Explanation:

a)Formula for per unit impedance for change of base is

Zpu2= Zpu1×(kV1/kV2)²×(kVA2/kVA1)

Zpu2: New per unit impedance

Zpu1: given per unit impedance

kV1: give base voltage

kV2: New bas votlage

kVA1: given bas power

kVA2: new base power

In the question

Zpu2=??

Zpu1= 0.3

kV2=24kV

kV1= 13.8 kV

kVA2= 1MVA ×1000= 1000 kVA

kVA1=500kVA

Zpu2= 0.3(13.8/24)²×(1000/500)

Zpu2= 0.198

b) to find ohmic impedance we will first calculate base value of impedance(Zbase). So,

Zbase= kV²/MVA

  Zbase= 13.8²/(500/1000)

  Zbase=380.88

Now that we have base value of impedance, Zbase, we can calculate actual ohmic value of impedance(Zactual) by using the following formula:

Zpu=Zactual/Zbase

0.3= Zactual/380.88

Zactual= 114.26 ohms

8 0
3 years ago
A cyclist travels at a speed of 21.6km/h.
klio [65]

Answer:

D.6.0m/s

Explanation:

5/18*21.6

=6.0m/s

3 0
3 years ago
The kinetic energy of an object increases as its ____ its potential energy
tankabanditka [31]
The kinetic energy of an object increases as its decreases <span>its potential energy as the sum of energy will remain constant.

In short, Your Answer would be "Decreases"

Hope this helps!</span>
8 0
3 years ago
(6) A 75 kg human total footprint area is 0.05 m2 when wearing winter boots. Suppose that you want to walk on snow that can at m
fredd [130]

Answer:

0.25m²

Explanation:

We know that the summation of forces in the vertical direction is zero

So

PA-mg=0

A=mg/p

So

Substituting

A= 75* 9.8/3*10^-3

=0.25m² which is the total shoe area

3 0
3 years ago
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