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True [87]
3 years ago
12

An Object moving 10 m/s undergoes acceleration for 6 seconds. If it moves 8 m to the left, find the acceleration

Physics
1 answer:
ch4aika [34]3 years ago
4 0
\Delta x= V_0t+ \frac{1}{2}at^{2} \\  \\ 8=10(6)+ \frac{1}{2}a(6)^{2} \\  \\ 8=60+ \frac{1}{2}(36)a \\  \\ 8=60+13a \\  \\ -52=13a \\  \\  \frac{-52}{13}=a \\  \\ \boxed{a=-4m/s^{2}}
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A metal block has a mass of 5 grams and a volume of 1 cm3. What is the density of a piece of the same identical metal but with a
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Answer:

ρ = Mass / Volume     definition of density

ρ  = 5 g / 1cm^3 = 5 g / cm^3

Since the other object is made of the same metal its density is the same:

ρ = 5 g/cm^3

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2 years ago
What is the word that goes with the definition “ a disturbance in space that causes a force”
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Gravity is the force that causes a "disturbance" in space between planets.

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3 years ago
The record for the highest speed achieved in alaboratory for a
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0.000234 seconds

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3 0
2 years ago
The blood pressure of human body is greater at the feet than at the brain. why?give reason​
SOVA2 [1]

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6 0
3 years ago
What is the repulsive force between two pith balls that are 8.00 cm apart and have equal charges of −25.0 nc? g?
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To calculate the force between two negative charges, we use the formula which is given by the Coulomb`s Law as

F=\frac{kq_{1}q_{2}  }{r^{2} }

Here, q_{1} andq_{2} are the charges on the pith balls, r is the separation between the charges and k is constant and its value is  8.99\times 10^9 N m^2/C^2.

Given  q_{1} =q_{2} =-25 nC=-25\times 10^{-9}C and  r=8 cm=8\times10^{-2} m.

Substituting these values in above formula we get,

F= 8.99\times 10^9 N m^2/C^2\frac{(-25\times 10^{-9}C)(-25\times 10^{-9}C)}{(8\times10^{-2} m)^2} \\\\\ F= 877929.7\times 10^{-9}  N\\\\F=8.8\times10^{-4}N

Thus, the repulsive force between two pith balls is 8.8\times10^{-4}N.

7 0
3 years ago
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