Question

An Object moving 10 m/s undergoes acceleration for 6 seconds. If it moves 8 m to the left, find the acceleration

Answer 1

$\Delta x= V_0t+ \frac{1}{2}at^{2} \\ \\ 8=10(6)+ \frac{1}{2}a(6)^{2} \\ \\ 8=60+ \frac{1}{2}(36)a \\ \\ 8=60+13a \\ \\ -52=13a \\ \\ \frac{-52}{13}=a \\ \\ \boxed{a=-4m/s^{2}}$