A drag racer starts her car from rest and accelerates at 11.9 m/s2 for the entire distance of 400 m. What is the speed of the ra
1 answer:
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Answer:
The average velocity of the car is, V = 74.04 m/s
Explanation:
Given data,
The initial velocity of the car, u = 0 m/s
The displacement of the ca, S = 1100 m
The time period of travel, t = 14 s
The velocity of the car at point k, v = 65 m/s
Using the II equation of motion,
S = ut + ½ at²
Substituting the given values,
1100 = 0 + ½ x a x 14²
a = 11.22 m/s²
Using the III equation of motion
v² = u² + 2 as
v = √(2as) (∵ u = 0)
Substituting,
v = √(2 x 11.22 x 1100)
= 157.11 m/s
The average speed of the car,
V = 74.04 m/s
Hence, the average velocity of the car is, V = 74.04 m/s
Answer:
On the magnitude of the charges, on their separation and on the sign of the charges
Explanation:
The magnitude of the electric force between two charges is given by
where
k is the Coulomb's constant
q1, q2 are the magnitudes of the two charges
r is the separation between the charges
From the formula, we see that the magnitude of the force depends on the following factors:
- magnitude of the two charges
- separation between the charges
Moreover, the direction of the force depends on the sign of the two charges. In fact:
- if the two charges have same sign, the force is repulsive
- if the two charges have opposite signs, the force is attractive