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3 years ago

Explain why the weather changes with the season's temperate climate zones.

1 answer:

3 0

Environments that have moderate rainfall spread year to year with sporadic droughts. Mild and warm- leads to summer(hot) cool and cold leads the winter

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What is the output force if the input force on the wheel is 100 N?

Levart [38]

The answer is B) and here's why:
since the radius of the wheel is 3 and the radius of the axle is 1 you multiply 3 by 1 which is 3. Then you multiply it with 100 so 3 x 100 is 300. But there is no 300 the closest answer is B)200. so B should be the answer

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3 years ago

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A ball is thrown straight up from point A, reaches a maximum height at point B, and then falls back to point C. Which of the fol

ratelena [41]

PE.....................

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3 years ago

Samuel adds a teaspoon of salt to a glass of water. He notices that the salt disappears. Samuel takes a sip to discover that the

nirvana33 [79]

The answer is physical change. This is a kind of change moving the form of a chemical substance, but not its chemical arrangement. Physical changes are used to isolate combinations into their constituent compounds, but cannot typically be used to distinct compounds into chemical elements or simpler compounds. When the salt dissolve in water it is a physical change. The chemical arrangement of the salt is not altered.

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4 years ago

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An asteroid that has an orbital period of 3 years will have an orbital with a semi-major axis of about _____ years.

Airida [17]

Answer:

An asteroid that has an orbital period of 3 years will have an orbital with a semi-major axis of about 2 years.

Explanation:

Given;

orbital period of 3 years, P = 3 years

To calculate the years of an orbital with a semi-major axis, we apply Kepler's third law.

Kepler's third law;

P² = a³

where;

P is the orbital period

a is the orbital semi-major axis

(3)² = a³

9 = a³

a = $a = \sqrt[3]{9} \\\\a = 2.08 \ years$

Therefore, An asteroid that has an orbital period of 3 years will have an orbital with a semi-major axis of about 2 years.

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3 years ago

<img src="https://tex.z-dn.net/?f=%5Chuge%20%5Cfrak%7B%E0%BC%86%20%20%5C%3A%20%20%5C%3A%20question%20%5C%3A%20%20%5C%3A%20%E0%BC

My name is Ann [436]

The crate is moving at constant velocity when the forces acting on it are

balanced.

The value of the force F required to pull the crate with constant velocity is; $\underline{F = \sqrt{2} \cdot \mu \cdot m\cdot g}$

Reasons:

Mass of the crate = m

Cross section of through = Right angled

Orientation (inclination) of the through to horizontal = 45°

Coefficient of kinetic friction = μ

Required:

The value of the required to pull the crate along the through at constant

velocity.

Solution:

When the through is moving at constant velocity, we have;

Friction force acting on crate = Force pulling the crate

Friction force = Normal reaction × Coefficient of kinetic friction

Normal reaction on an inclined plane = $\mathbf{F_N}$

Each side of the through gives a normal reaction.

The vertical component of the normal reaction on each side of the through

is therefore;

$F_N$ ·j = $\mathbf{F_N}$ × sin(θ)

The sum of the vertical component = $F_N$ ·j + $F_N$ ·j = 2· $F_N$ ·j = 2· $F_N$ ×sin(θ)

The sum of the vertical component of the normal reactions = The weight of the crate

Therefore;

2· $F_N$ ×sin(θ) = m·g

θ = 45°

Therefore;

2· $F_N$ ×sin(45°) = m·g

$\displaystyle sin(45^{\circ}) = \mathbf{\frac{\sqrt{2} }{2}}$

Therefore;

$\displaystyle 2 \cdot F_N \cdot sin(45^{\circ}) = 2 \cdot F_N \times \frac{\sqrt{2} }{2} = \sqrt{2} \cdot F_N$

$\displaystyle F_N = \mathbf{ \frac{m \cdot g}{\sqrt{2} }}$

Which gives;

$\displaystyle Force \ required, \ F = Sum \of \ friction \ forces \ = 2 \times F_N \times \mu = \mathbf{ 2 \times \frac{m \cdot g}{\sqrt{2} } \times \mu}$

$\displaystyle Force \ required, \ F = 2 \times \frac{m \cdot g}{\sqrt{2} } \times \mu = \mathbf{ \sqrt{2} \cdot \mu \cdot m \cdot g}$

Force required to pull the crate at constant velocity, F = √2·μ·m·g

Learn more about force of friction here:

brainly.com/question/6561298

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2 years ago

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