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Ksenya-84 [330]

3 years ago

15

C2F4 effuses through a barrier at a rate of 4.6x10-6 mol/hour, while an unknown gas effuses at a rate of 5.8x10-6 mol/hour. What

is the molar mass of the unknown compound?

1 answer:

umka21 [38]3 years ago

5 0

The molar mass of the unknown compound is calculated as follows

let the unknown gas be represented by letter Y

Rate of C2F4/ rate of Y = sqrt of molar mass of gas Y/ molar mass of C2F4

= (4.6 x10^-6/ 5.8 x10^-6) = sqrt of Y/ 100

remove the square root sign by squaring in both side

(4.6 x 10^-6 / 5.8 x10^-6)^2 = Y/100

= 0.629 =Y/100

multiply both side by 100

Y= 62.9 is the molar mass of unknown gas

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A gas of 3.4 moles occupies a volume of 0.046 L at 298 K. What is the pressure in kPa?

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Answer : The correct option is, $2.1\times 10^5kPa$

Explanation :

To calculate the pressure of gas we are using ideal gas equation as:

$PV=nRT$

where,

P = pressure of gas = ?

V = volume of gas = 0.046 L

n = number of moles of gas = 3.4

R = gas constant = 8.314 L.kPa/mol.K

T = temperature of gas = 298 K

Now put all the given values in the above formula, we get:

$P\times (0.046L)=(3.4mol)\times (8.314L.kPa/mol.K)\times (298K)$

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1. Ba(OH)2<br> give the correct name for the ionic and covalent compounds

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Answer:

barium hydroxide.......

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3 years ago

Determine the energy of 1.70 mol of photons for each of the following kinds of light. (Assume three significant figures.)PART A

BabaBlast [244]

<u>Answer:</u>

<u>For A:</u> The energy of the given amount of photons for infrared radiation is $1.271\times 10^5J$

<u>For B:</u> The energy of the given amount of photons for infrared radiation is $4.026\times 10^5J$

<u>For C:</u> The energy of the given amount of photons for infrared radiation is $1.355\times 10^6J$

<u>Explanation:</u>

The relationship between energy and frequency is given by Planck's equation, which is:

$E=n\rimes N_A\times \frac{hc}{\lambda}$ ......(1)

where,

h = Planck's constant = $6.62\times 10^{-34}Js$

E = energy of the light

c = speed of light = $3\times 10^8m/s$

$\lambda$ = wavelength of light

$N_A$ = Avogadro's number = $6.022\times 10^{23}$

n = number of moles of photons = 1.70 moles

Conversion factor used: $1m=10^9nm$

<u>For A:</u>

Wavelength of infrared radiation = $1600nm=1.6\times 10^6m$

Putting values in equation 1, we get:

$E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{1.6\times 10^{-6}}\\\\E=1.271\times 10^5J$

Hence, the energy of the given amount of photons for infrared radiation is $1.271\times 10^5J$

<u>For B:</u>

Wavelength of visible light = $505nm=5.05\times 10^7m$

Putting values in equation 1, we get:

$E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{5.05\times 10^{-7}}\\\\E=4.026\times 10^5J$

Hence, the energy of the given amount of photons for infrared radiation is $4.026\times 10^5J$

<u>For C:</u>

Wavelength of ultraviolet radiation = $150nm=1.5\times 10^7m$

Putting values in equation 1, we get:

$E=1.7\times 6.022\times 10^{23}\times \frac{6.62\times 10^{-34}\times 3\times 10^8}{1.5\times 10^{-7}}\\\\E=1.355\times 10^6J$

Hence, the energy of the given amount of photons for infrared radiation is $1.355\times 10^6J$

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3 years ago

At 125 C the pressure of a sample of oxygen (O2) is 2.25 atm. What will the

brilliants [131]

Answer:

1.68 atm

Explanation:

Applying

P/T = P'/T'................... Equation 1

Where P = Initial pressure, T = Initial Temperature, P' = Final pressure, T' = Final Temperature.

Make P' The subject of the equation

P' = PT'/T.............. Equation 2

From the question,

Given: P = 2.25 atm, T = 125°C = (125+273) K = 398 K, T' = 25°C = (25+273) K = 298 K.

Substitute these values into equation 2

P' = (2.25×298)/398

P' = 1.68 atm

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