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Allisa [31]
2 years ago
7

How many grams of sodium chloride are dissolved in 375 ml of a 0.90% saline solution?

Chemistry
1 answer:
liq [111]2 years ago
3 0

Answer:

337.5 g NaCl

Explanation:

.90% saline solution = 90g saline (NaCl)/100mL water (H2O)

1. Use 375 mL to find mass

375 mL × (90 g NaCl/100 mL) = 337.5 g NaCl in 375 mL .9% saline solution

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The concentration of ozone in ground-level air can be determined by allowing the gas to react with an aqueous solution of potass
Natali5045456 [20]

Answer:

a) 2KI + O₃ + H₂O ----> I₂ + O₂ + 2KOH

b) Ozone concentration = 0.246 ppb

Explanation:

a) The balanced equation for the reaction is

2KI + O₃ + H₂O ----> I₂ + O₂ + 2KOH

b) We first convert 17 μg of KI to number of moles

Number of moles = (mass)/(molar mass)

Molar mass of KI = 166 g/mol

Mass of KI that reacted = 17 μg = (17 × 10⁻⁶) g

Number of moles = (17 × 10⁻⁶)/166

Number of moles of KI that reacted = (1.0241 × 10⁻⁷) moles

From the stoichiometric balance of the reaction,

2 moles of KI reacts with 1 mole of O₃

Then, (1.0241 × 10⁻⁷) moles of KI will react with (1.0241 × 10⁻⁷ × 1/2) moles of O₃

Number of moles of O₃ that reacted = (5.12 × 10⁻⁸) moles.

To express the amount of O₃ in 10.0 L of air in ppb, we need to convert the amount of O₃ that reacted.

Mass = (number of moles) × (molar mass)

Molar mass of O₃ = 48 g/mol

Mass of O₃ that reacted = (5.12 × 10⁻⁸) × 48 = 0.0000024578 g = (2.46 × 10⁻⁶) g

Concentration in ppb = (Mass of solute in μg)/(volume of solution in L)

Mass of solute = Mass of O₃ = (2.46 × 10⁻⁶) g = 2.46 μg

Volume of solution = 10.0 L

Concentration of O₃ in air in ppb = 2.46/10 = 0.246 ppb

4 0
2 years ago
Aq. sodium oxalate reacts with aq calcium chioride to form sd nd soum ce
STatiana [176]
Na2C2O4(aq) + CaCl2(aq) -----> 2NaCl(aq) + CaC2O4(s)

Here, CaC2O4(s) is a precipitate in the reaction as a result of precipitation reaction or double displacement reaction.

As we know that double displacement reaction two metal ions displaces each other from their salt solutions.

As we know that precipitation reaction is a reaction in which precipitate is formed.
4 0
3 years ago
A 0.4647-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.01962 mol of
Scilla [17]

Answer:

The essence including its given problem is outlined in the following segment on the context..

Explanation:

The given values are:

Moles of CO₂,

x = 0.01962

Moles of water,

\frac{y}{2} =0.01961

y=2\times 0.01961

  =0.03922

Compound's mass,

= 0.4647 g

Let the compound's formula will be:

C_{x}H_{y}O_{z}

Combustion's general equation will be:

⇒  C_{x}H_{y}O_{z}+x+(\frac{y}{4}-\frac{z}{2}) O_{2}=xCO_{2}+\frac{y}{2H_{2}O}

On putting the estimated values, we get

⇒  12\times x=1\times y+16\times z=0.4647

⇒  12\times 0.01962+1\times 0.03922+16\times z=0.4647

⇒  0.27466+16z=0.4647

⇒                     z=0.01187

Now,

x : y : z = 0.01962:0.03922:0.01187

           = \frac{0.01962}{0.0118}:\frac{0.03922}{0.0188}:\frac{0.0188}{0.0188}

           = 1.6:3.3:1.0

           = 3:6:2

So that the empirical formula seems to be "C₃H₆O₂".

8 0
2 years ago
Help please science (7th grade)
hoa [83]

Answer:

17

Explanation:

Don't mind the random letters

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8 0
2 years ago
Read 2 more answers
Pluto is a planet<br><br> True<br> False
koban [17]

Answer:

False

Explanation:

It's classified as a dwarf planet, but not technically a planet.

6 0
2 years ago
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