you produce 115 grams of water in a combustion reaction. how much methane do you need in grams for this to react?
1 answer:
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Explanation:
Let the volume of the solution be 100 ml.
As the volume of glycol = 50 = volume of water
Hence, the number of moles of glycol =
=
=
= 0.894 mol
Hence, number of moles of water =
= 2.77
As glycol is dissolved in water.
So, the molality =
= 17.9
Therefore, the expected freezing point =
=
Thus, we can conclude that the expected freezing point is .
Answer:
1.1 × 10⁻⁴ M
Explanation:
Let's consider the following double displacement reaction.
CuCl₂(aq) + 2 AgNO₃(aq) → 2 AgCl(s)+ Cu(NO₃)₂(aq)
We can establish the following relations:
- The molar mass of AgCl is 143.32 g/mol.
- The molar ratio of AgCl to CuCl₂ is 2:1
The moles of CuCl₂ that reacted to produce 7.7 mg of AgCl are:
The molarity of CuCl₂ is: