Its B i believe, Storms and currents can bring in sediments from other places
The question is incomplete . The complete question is :
100 mg of an unknown protein are dissolved in enough solvent to make 5.00mL of solution. The osmotic pressure of this solution is measured to be 0.107atm at 25.0°C. Calculate the molar mass of the protein. Round your answer to 3 significant digits.
Answer: The molar mass of the protein is 
Explanation:


where,
= osmotic pressure of the solution = 0.107 atm
i = Van't hoff factor = 1 (for non-electrolytes)
Mass of solute (protein) = 100 mg = 0.1 g (Conversion factor: 1 g = 1000 mg)
Volume of solution = 5.00 mL
R = Gas constant = 
T = temperature of the solution = ![25^oC=[273+25]=298K](https://tex.z-dn.net/?f=25%5EoC%3D%5B273%2B25%5D%3D298K)
Putting values in above equation, we get:


Hence, the molar mass of the protein is 
<span>Ernest Rutherford was the scientist that developed a model of the atom that looked like a nucleus surrounded by electrons.
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Answer : The concentration of
and
at equilibrium is, 0.0158 M and 0.00302 M respectively.
Explanation :
First we have to calculate the concentration of 



Now we have to calculate the value of equilibrium constant (K).
The given chemical reaction is:

Initial conc. 0.0163 0.00415 0.00276
At eqm. (0.0163-2x) (0.00415+x) (0.00276+x)
As we are given:
Concentration of
at equilibrium = 0.00467 M
That means,
(0.00415+x) = 0.00467
x = 0.00026 M
Concentration of
at equilibrium = (0.0163-2x) = (0.0163-2(0.00026)) = 0.0158 M
Concentration of
at equilibrium = (0.00276+x) = (0.00276+0.00026) = 0.00302 M