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Nastasia [14]
3 years ago
11

List the celestial bodies from smallest to largest based on their actual size.

Chemistry
1 answer:
Usimov [2.4K]3 years ago
3 0
From largest to smallest they are: Universe, galaxy, solar system, star, planet, moon and asteroid.
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What is the mole fraction of water in pure water
irinina [24]
In pure water, all of the molecules in the liquid are water molecules so the mole fraction is 1 (100 % H2O, 55 mol/L). In sea water, the concentration of water molecules in the solution is less than that of pure water so the vapor pressure of sea water is also lower.
5 0
3 years ago
Which model of the atom explains the orbitals of electrons as waves
Zielflug [23.3K]

Answer:

The Bohr model of the atom explains the reactivity of all atoms.

6 0
2 years ago
A solution of H 2 SO 4 ( aq ) H2SO4(aq) with a molal concentration of 8.01 m 8.01 m has a density of 1.354 g / mL . 1.354 g/mL.
anzhelika [568]

Answer:

[H₂SO₄] = 6.07 M

Explanation:

Analyse the data given

8.01 m → 8.01 moles of solute in 1kg of solvent.

1.354 g/mL → Solution density

We convert the moles of solute to mass → 8.01 mol . 98g /1mol = 785.4 g

Mass of solvent = 1kg = 1000 g

Mass of solution = 1000g + 785.4 g = 1785.4 g

We apply density to determine the volume of solution

Density = Mass / volume → Volume = mass / density

1785.4 g / 1.354 g/mL = 1318.6 mL

We need this volume in L, in order to reach molarity:

1318.6 mL . 1L / 1000mL = 1.3186 L ≅ 1.32L

Molarity (mol/L) → 8.01 mol / 1.32L = 6.07M

4 0
3 years ago
Read 2 more answers
Someone who knows how to do this please help me!!!!!
Sindrei [870]
It may just be my internet but the picture is just white. maybe try reposting this..?
5 0
2 years ago
The density of a gaseous compound is 1.623 g/l at stp determine the molar mass of the compound
victus00 [196]
<span>The molar mass of the compound is 36.355 g/mol. This is calculated by knowing that 1 mol of gas fills 22.4 L of volume, so 1.623 g/L = X g/mol * 1/22.4 mol/L -> 1.623 g/L * 22.4 L/mol = X g/mol -> 36.355 g/mol = X g/mol</span>
4 0
3 years ago
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