The volume of the textbook calculated by the student written to 3 significant figures is 992cm³
- According to this question, a student calculates the volume of his textbook and arrived at an answer of 991.880 cm³.
- To round up this digit to 3 significant figures, which means that only 3 significant numbers should appear in the answer.
- To do this, the number after the third number is 8, which means we can round up the value of 1 to 2. Hence, the volume of the textbook calculated by the student is 992cm³ in 3 s.f.
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2.83 days into hours = 2.83 x 24 = 67.92 hours
67.92 hours into minute = 67.92 x 60 = 4075.2 minutes
4075.2 minutes into seconds = 4075.2 x 60 = 244,512 seconds.
Answer:
70mol
Explanation:
The equation of the reaction is given as:
2C₂H₂ + 5O₂ → 4CO₂ + 2H₂O
Given parameters:
Number of moles of acetylene = 35.0mol
Number of moles of oxygen in the tank = 84.0mol
Unknown:
Number of moles of CO₂ produced = 35.0mol
Solution:
From the information given about the reaction, we know that the reactant that limits this combustion process is acetylene. Oxygen is given in excess and we don't know the number of moles of this gas that was used up. We know for sure that all the moles of acetylene provided was used to furnish the burning procedure.
To determine the number of moles of CO₂ produced, we use the stoichiometric relationship between the known acetylene and the CO₂ produced from the balanced chemical equation:
From the equation:
2 moles of acetylene produced 4 moles of CO₂
∴ 35.0 mol of acetylene would produced:
= 70mol
Colorimetric methods of analysis make use of Color changes in reagents to decipher the concentration of solutions.
Therefore, color completes the sentence
<h3>Colourimetric analysis</h3>
Generally, Colorimetric analysis is used to know the concentration of a chemical element in a solution while using colour indicators or reagents.
Therefore
Colorimetric methods of analysis are based on having a reagent that changes Color as a function of the concentration of the analyte.
Color
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Answer:
Oxidation state shows the total number of electrons which have been removed from an element (a positive oxidation state) or added to an element (a negative oxidation state) to get to its present state
