(2C+2+N-X-H)/2
(2*7+2+0-0-8)/2
4
Answer:
EXPERIMENT: THE CABBAGE INDICATOR
Here are your goals for this lesson:
Use indicator for each substance to determine if substance is an acid or a base
Summarize results and the experimental method
You can use the natural indicator in red cabbage juice to determine which household liquids are acids or bases. If no change in the color of the cabbage juice takes place, the liquid is neither an acid nor base; it is neutral.
Acids and bases are opposites. When an acids and base are mixed, they neutralize each other. You can use an indicator to see the neutralized reaction. The cabbage juice will change color when the liquids are neutralized.
Online Lab
This video will demonstrate how an indicator, in this case, cabbage indicator, can be used to determine whether a solution is acidic or basic. As you watch the video, remember to record your data and observations to use to present your findings.
Compile a summary of your findings from this experiment. Include your hypothesis, observations, data, and conclusions. Be sure to answer the questions below as well as explaining the method and results.
r.
Explanation:
Answer:
120.0 mL.
Explanation:
- As it is known that the no. of millimoles of a solution before dilution is equal to the no. of millimoles after dilution.
We suppose that the initial W% of methanol is 100.0 %
<em>∴ (W%V) before dilution = (W%V) after dilution.</em>
W% before dilution = 100.0 %, V before dilution = 18.0 mL.
W% after dilution = 15.0 %, V after dilution = ??? mL.
<em>∴ V after dilution = (W%V) before dilution/W% after dilution = </em>(100.0 %)(18.0 mL)/(15.0%)<em> = 120.0 mL.</em>
Answer:
Therefore the Chlorine electron configuration will be 1s22s22p63s23p5. The configuration notation provides an easy way for scientists to write and communicate how electrons are arranged around the nucleus of an atom.
Explanation:
Answer:
2 HgO → 2 Hg + O2
Explanation:
Decomposition is when one reactant breaks down into two or more products due to heat, light or electricity
Here mercury (II) oxide goes through thermal decomposition to make mercury and oxygen
