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3 years ago

What is the bond order of N2+

1 answer:

6 0

N2 has the optimal bond order of 3. To form N2+, one bonding electron is removed, giving a bond order of 2.5. Similarly, to form N2-, one antibonding electron is added, also giving a bond order of 2.5.

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The box in the above picture is falling from the top of a building to the ground. Two major forces are acting on the box as it f

MAVERICK [17]

Answer:

I think it's B

Explanation:

apologies if I get this wrong

8 0

3 years ago

Read 2 more answers

Be sure to answer all parts. Consider the reaction N2(g) + 3H2(g) → 2NH3(g)ΔH o rxn = −92.6 kJ/mol If 4.0 moles of N2 react with

Sphinxa [80]

Answer : The work done is, $1.98\times 10^4J$

Explanation :

The given balanced chemical reaction is:

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

When 4 moles of $N_2$ react with 12 moles of $H_2$ then it gives 8 moles of $NH_3$

First we have to calculate the change in moles of gas.

Moles on reactant side = Moles of $N_2$ + Moles of $H_2$

Moles on reactant side = 4 + 12 = 16 moles

Moles on product side = Moles of $NH_3$

Moles on reactant side = 8 moles

Change in moles of gas = 16 - 8 = 8 moles

Now we have to calculate the change in volume of gas.

Using ideal gas equation:

$PV=nRT$

where,

P = Pressure of gas = 1.0 atm

V = Volume of gas = ?

n = number of moles of gas = 8 mole

R = Gas constant = $0.0821L.atm/mol.K$

T = Temperature of gas = $25^oC=273+25=298K$

Putting values in above equation, we get:

$1.0atm\times V=8mole\times (0.0821L.atm/mol.K)\times 298K$

$V=195.7L$

As the number of moles of gas decreased. So, the volume also deceased. Thus, the volume of gas will be, -195.7 L

Now we have to calculate the work done.

Formula used :

$w=-p\Delta V$

where,

w = work done

p = pressure of the gas = 1.0 atm

$\Delta V$ = change in volume = -195.7 L

Now put all the given values in the above formula, we get:

$w=-p\Delta V$

$w=-(1.0atm)\times (-195.7L)$

$w=195.7L.artm=195.7\times 101.3J=19824.41J=1.98\times 10^4J$

conversion used : (1 L.atm = 101.3 J)

Thus, the work done is, $1.98\times 10^4J$

6 0

3 years ago

How much water would I need to add to 700 mL of a 2.7 M KCl solution to make a 1.0 M solution?

geniusboy [140]

Answer:

$1190\ \text{mL}$

Explanation:

$M_1$ = Initial Concentration of KCl = 2.7 M

$V_1$ = Volume of KCl = 1 M

$M_2$ = Final concentration of KCl = 1 M

$V_2$ = Amount of water

We have the relation

$M_1V_1=M_2V_2\\\Rightarrow V_2=\dfrac{M_1V_1}{M_2}\\\Rightarrow V_2=\dfrac{2.7\times 700}{1}\\\Rightarrow V_2=1890\ \text{mL}$

The amount of water that is to be added is $1890-700=1190\ \text{mL}$ .

3 0

3 years ago

How would a bar magnet orient itself relative to this planet's magnetic field?

Maksim231197 [3]

The magnet's north pole would point to the Earth's south pole and the magnet's south pole would point to the Earth's north pole.

<u>Explanation</u>:

There is a magnetic pole in the earth and the magnetic poles of the earth run using the equator and it has both the closures at the arctic pole and the Antarctic pole. The attractive positive field or the north pole is situated in the arctic zone and the south pole is situated in the Antarctic zone.

The magnetic positive field or the north pole is situated in the arctic zone. Any magnet which is allowed to rotate whenever suspended on the outside of the earth will align itself with the magnetic field of the earth. That is the way the bar magnet orients itself comparative with this current planet's magnetic field.

7 0

3 years ago

Which of the following information can be determined from this isotope: sodium 23 and why?

JulsSmile [24]

<h2>YOUR ANSWER Is number of istopes</h2>

✌️

4 0

3 years ago