Rectangular and polar forms are two forms of equations that translates to plot. In this case, the two forms are convertible to each other by the expressions:
r sin theta = y
r cos theta = x
x2 + y2 = r2
we are given the polar expression r csc theta = 8 and is asked to convert to rectangular form.
in this case, csc theta is equal to 1/ sin theta. thys
r / sin theta = 8
in order to make use of the equations above, then
we multiply r to both numerator and denominator in the left side, that is
r^2 / r sin theta = 8
x2+y2 / y = 8
x 2 + y2 = 8y
We know, area = length * width
56 = l * 4
l = 56 / 4
l = 14
So, the length is 14
Hope this helps!
Given:
The measures of the angles in a triangle are in the ratio of 2:2:4.
To find:
The exterior angle that is adjacent to the largest angle.
Solution:
Let the interior angles of the triangle are 2x, 2x and 4x respectively.
According to the angle sum property, the sum of interior angles of a triangle is 180 degrees.
Clearly, x=22.5>1, so 4x is the largest angle between 2x, 2x and 4x.
Now,
Let the required exterior angle that is adjacent to the largest angle be y.
Interior angle and adjacent exterior angles are supplementary, so their sum is 180 degrees.
Therefore, the exterior angle that is adjacent to the largest angle is 90°.
The answer is three dollars and fifty cents
First remember the following kinematic equations:
a = g
vf = g * t + vo
rf = (1/2) * g * t ^ 2 + vo * t + ro
g: gravity
t: time
vf: final speed
Vo: initial speed
For this case what we should do is to choose the equation that best suits each statement.
We have then:
GroupA: h (t) = - 4.9 * t ^ 2 + 19 * t
Group B: h (t) = - 16 * t ^ 2 + 50 * t
Group C: h (t) = - 4.9 * t ^ 2 +19
Group D: h (t) = - 16 * t ^ 2 +50
