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3 years ago

Please help solve this, I solved it on my own but I think my calculations are wrong. here is the problem,

Mathematics

2 answers:

denis-greek [22]3 years ago

5 0

Hi there! Hopefully this helps!

----------------------------------------------------------------------------------------------------------

<h2>Answer: 12</h2><h2>~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~</h2>

First we need to <em><u>substitute the value of the variable into the expression</u></em> and simplify.

b-(b+a×4c÷4) = 1 - (1 + -6 × 4(2) ÷ 4).

Now we need to solve 1 - (1 + -6 × 4(2) ÷ 4).

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

1 - (1 + -6 × 4(2) ÷ 4)

| First, we cancel out 4 and 4.

1 - (1 - 6 × 2)

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Next, we multiply -6 and 2 to get -12.

1 - (1 - 12)

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Then we subtract 12 from 1 to get -11.

1 - (-11)

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

The opposite of -11 is 11.

1 + 11.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

<h2 /><h2>Add 1 and 11 to get, you guessed it, 12!</h2>

Lostsunrise [7]3 years ago

5 0

Answer:

Answer: 12

Hope this helps

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P(x)=(x-2)(x-4)(x-5)

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The constants of a polynomial is the term that has no variable attached to it.

<h3>The constant term</h3>

To determine the constant, we simply multiply the constant term in each factor of the polynomial.

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<h3 /><h3>Polynomial P(x) = (x-2)(x-4)(x-5)</h3>

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<h3>Polynomial P(x) = (x-2)(x-4)(x+5)</h3>

$Constant = -2 \times -4 \times 5$

$Constant = 40$

Hence, the constant is 40

<h3>Polynomial P(x) =1/2(x-2)(x-4)(x+5)</h3>

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Hence, the constant is 20

<h3>Polynomial P(x) = 5(x-2)(x-4)(x+5)</h3>

$Constant = 5 \times -2 \times -4 \times 5$

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Hence, the constant is 200

$Constant = -5 \times -2 \times -4 \times 5$

$Constant = -200$

Hence, the constant is -200