We are given the following equation and want to find the possible values of x
Subtract both sides by 3x
Now, we have this weird equation. Since -15 is NOT equal 15 and there is no other way we could have solved for x, there is no real solution to the given equation.
In other words, there is no value of x that makes the equation true.
Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
The correct option is A. x – 1 < n < 3x + 5
Step-by-step explanation:
In a triangle sum of any two sides is always greater than the third side.
Now, the sides of the triangle are given to be :
2x + 2, x + 3 , n
Now, first take 2x + 2 and x + 3 as two sides and the side of length n as third side.
By using the property that sum of two sides is always greater than the third side in a triangle.
⇒ 2x + 2 + x + 3 > n
⇒ 3x + 5 > n ......(1)
Now, take n and x + 3 as two sides and the side of length 2x + 2 as the third side of triangle.
So, by the property, we have :
n + x + 3 > 2x + 2
⇒ n > x - 1 ...........(2)
From both the equations (1) and (2) , We get :
x – 1 < n < 3x + 5
Therefore, The correct option is A. x – 1 < n < 3x + 5
Answer:
14.7
Step-by-step explanation:
Perhaps your equation is ...
f(t) = N·e^(-0.2174t)
We want f(6) = 4, so ...
4 = N·e^(-0.2174·6) = N·e^-1.3044 ≈ 0.2713N
N = 4/0.2713 = 14.7 . . . . milligrams
The dose amount was about 14.7 mg.
C= 2 x r where r = 8
C = 2 x 8
C = 16.
Hope I helped:)
