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2 years ago

What is electricity defined as

Engineering

1 answer:

antoniya [11.8K]2 years ago

4 0

Answer:

Exact answer: a form of energy resulting from the existence of charged particles (such as electrons or protons), either statically as an accumulation of charge or dynamically as a current.

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Determine the design moment strength for a W21x73 steel beam with a simple span of 18 ft when lateral bracing for the compressio

SVETLANKA909090 [29]

This question is incomplete, the complete question is;

Determine the design moment strength (ϕMn) for a W21x73 steel beam with a simple span of 18 ft when lateral bracing for the compression flange is provided at the ends only (i.e., Lb = 18 ft). Report the result in kip-ft.

Use Fy=50 ksi and assume Cb=1.0 (if needed).

Answer: the design moment strength for the W21x73 steel beam is 566.25 f-ft

Explanation:

Given that;

section W 21 x 73 steel beam;

now from the steel table table for this section;

Zx = Sx = 151 in³

also given that; fy = 50 ksi and Cb = 1.0

QMn = 0.9 × Fy × Zx

so we substitute

QMn = 0.9 × 50 × 151

QMn = 6795 k-inch

we know that;

12inch equals 1 foot

QMn = 6795 k-inch / 12

QMn = 566.25 f-ft

Therefore the design moment strength for the W21x73 steel beam is 566.25 f-ft

7 0

3 years ago

Thick fluids such as asphalt and waxes and the pipes in which they flow are often heated in order to reduce the viscosity of the

Gala2k [10]

Answer:

what id the answer

Explanation:

7 0

2 years ago

water flows in a horizontal constant-area pipe; the pipe diameter is 75 mm and the average flow speed is 5 m/s. At the pipe inle

Veronika [31]

Answer:

Head loss = 28.03 m

Explanation:

According to Bernoulli's theorem for fluids we have

$\frac{P}{\gamma _{w}}+\frac{V^{2}}{2g}+z=Constant$

Applying this between the 2 given points we have

$\frac{P_{1}}{\gamma _{w}}+\frac{V_{1}^{2}}{2g}+z_{1}=\frac{P_{2}}{\gamma _{w}}+\frac{V_{2}^{2}}{2g}+z_{2}+h_{l}$

Here $h_{l}$ is the head loss that occurs

$\therefore h_{l}=\frac{P_{1}}{\gamma _{w}}+\frac{V_{1}^{2}}{2g}+z_{1}-\frac{P_{2}}{\gamma _{w}}-\frac{V_{2}^{2}}{2g}-z_{2}$

Since the pipe is horizantal we have $z_{1}-z_{2}=0$

Applying contunity equation between the 2 sections we get

$A_{1}V_{1}=A_{2}V_{2}\\\\\therefore V_{1}=V_{2}(\because A_{1}=A_{2})$

Since the cross sectional area of the both the sections is same thus the speed

is also same

Using this information in the above equation of head loss we obtain

$h_{l}=\frac{1}{\gamma _{w}}(P_{1}-P_{2})$

Applying values we get

$h_{l}=\frac{1}{9810}\times (275\times 10^{3})m\\\\\therefore h_{l}=28.03m$

3 0

3 years ago

PLEASE LOOK AT MY PROFILE AND IF YOU KNOW THE ANSWERS CAN YOU ANSWER THEM PLEASE. IM ON A TIMED ASSIGNMENT!!!!

Arturiano [62]

Answer:

Explanation:

6 0

3 years ago

The final position of a car can be predicted with the following equation: Position = -2.5 (time) + 25 Where is the car’s positio

nekit [7.7K]

Answer:

The car's position at 3.0 seconds is 17.5 meters. The car will reach 0.0 meters at 10 seconds.

Explanation:

You can rewrite the equation as P= -2.5t+25. t=time and P is equal to position; so you will plug in 3.0 seconds into t. The equation will now look like: P = -2.5(3.0)+25

P = -2.5(3.0) + 25

P = -7.5 + 25

P = 17.5 meters

Now, to find when the car reaches 0.0 meters, we will plug that into P since P = position and will solve for t.

P = -2.5t + 25

0.0 = -2.5t + 25

-25 -25

-25 = -2.5t

-25/-2.5 = -2.5t/-2.5

10 = t

So the car will reach 0.0 meters at 10 seconds.

8 0

3 years ago