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grandymaker [24]
2 years ago
12

Can someone please help me this is urgent!?

Engineering
2 answers:
Thepotemich [5.8K]2 years ago
8 0

Answer:

it would be C

Explanation:

if you look at the times 0-2 you see it goes to 2.0 so now it cant be A or D now if you look at times 2-4 you see it goes to 3.0 so now B isnt right and then 4-6 its stays at 3.0 so now its definitely C

Vlad1618 [11]2 years ago
5 0

Answer: my answer would be C.

Explanation:

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That's a really nice question sadly I don't know the answer I'm replying to you cuz I'm tryna get points so... Sorry

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Is 4/16 equal in measurement to 1/4
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Explanation:

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Read 2 more answers
1 import java.util.Scanner; 3 public class EqualityAndRelational { 4 public static void main (String args) args) { int userBonus
Anastaziya [24]

Missing Part of the Question

Complete the expression so that userPoints is assigned with 0 if userBonus is greater than 20 (second branch). Otherwise, userPoints is assigned with 10 (first branch

import java.util.Scanner;

public class EqualityAndRelational {

public static void main (String args) args) {

int userBonus; int userPoints;

userPoints=0;

Scanner scnr = new Scanner(System.in);

userBonus = scnr.nextInt();

// Program will be tested with values : 15, 20, 25, 30, 35. 12 13 14 15 16 17 18 19

( Your solution goes here)

{

userPoints= 10 ;

}

else {

userPoints = 0;

}

}

}

Answer;

Replace

( Your solution goes here)

With

if(userBonus>20).

The full program becomes

import java.util.Scanner;

public class EqualityAndRelational {

public static void main (String args) args) {

int userBonus; int userPoints;

userPoints=0;

Scanner scnr = new Scanner(System.in);

userBonus = scnr.nextInt();

// Program will be tested with values : 15, 20, 25, 30, 35. 12 13 14 15 16 17 18 19

if(userBonus>20)

{

userPoints= 10 ;

}

else {

userPoints = 0;

}

}

}

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3 years ago
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Iteru [2.4K]

Answer:

This should be true because program is a software and mouse and keyboard are specific computer hardware to make your exsperience with a computer more efficent and faster.

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