If you add 10 J of heat to a system so that the final temperature of the system is 200K, what is the change in entropy of the sy
1 answer:
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Answer:
γ =0.01, P=248 kN
Explanation:
Given Data:
displacement = 2mm ;
height = 200mm ;
l = 400mm ;
w = 100 ;
G = 620 MPa = 620 N//mm²; 1MPa = 1N//mm²
a. Average Shear Strain:
The average shear strain can be determined by dividing the total displacement of plate by height
γ = displacement / total height
= 2/200 = 0.01
b. Force P on upper plate:
Now, as we know that force per unit area equals to stress
τ = P/A
Also, τ = Gγ
By comapring both equations, we get
P/A = Gγ ------------ eq(1)
First we need to calculate total area,
A = l*w = 400 * 100= 4*10^4mm²
By putting the values in equation 1, we get
P/40000 = 620 * 0.01
P = 248000 N or 2.48 *10^5 N or 248 kN
Answer:
64.11% for 200 days.
t=67.74 days for R=95%.
t=97.2 days for R=90%.
Explanation:
Given that
β=2
Characteristics life(scale parameter α)=300 days
We know that Reliability function for Weibull distribution is given as follows
Given that t= 200 days
R(200)=0.6411
So the reliability at 200 days 64.11%.
When R=95 %
by solving above equation t=67.74 days
When R=90 %
by solving above equation t=97.2 days