Answer:C 0.12 V
Explanation:
Given
Concentration of ![Fe^{2+} M_1=0.40 M](https://tex.z-dn.net/?f=Fe%5E%7B2%2B%7D%20M_1%3D0.40%20M)
Concentration of ![Ni^{2+} M_2=0.002 M](https://tex.z-dn.net/?f=Ni%5E%7B2%2B%7D%20M_2%3D0.002%20M)
Standard Potential for Ni and Fe are
and ![V_1=-0.44 V](https://tex.z-dn.net/?f=V_1%3D-0.44%20V)
![\Delta V=V_2-V_1-\frac{0.0592}{2}\log (\frac{M_1}{M_2})](https://tex.z-dn.net/?f=%5CDelta%20V%3DV_2-V_1-%5Cfrac%7B0.0592%7D%7B2%7D%5Clog%20%28%5Cfrac%7BM_1%7D%7BM_2%7D%29)
![\Delta V=-0.25-(-0.44)-\frac{0.0592}{2}\log (\frac{0.4}{0.002})](https://tex.z-dn.net/?f=%5CDelta%20V%3D-0.25-%28-0.44%29-%5Cfrac%7B0.0592%7D%7B2%7D%5Clog%20%28%5Cfrac%7B0.4%7D%7B0.002%7D%29)
![\Delta V=0.12\ V](https://tex.z-dn.net/?f=%5CDelta%20V%3D0.12%5C%20V)
Answer:
Gs = 2.647
e = 0.7986
Explanation:
We know that moist unit weight of soil is given as
![\gamma_m \ or\ bulk\ density = \frac{(Gs+Se)\times \gamma_w}{(1+e)}](https://tex.z-dn.net/?f=%5Cgamma_m%20%5C%20or%5C%20bulk%5C%20density%20%3D%20%5Cfrac%7B%28Gs%2BSe%29%5Ctimes%20%5Cgamma_w%7D%7B%281%2Be%29%7D)
where,
= moist unit weight of the soil
Gs = specific gravity of the soil
S = degree of saturation
e = void ratio
= unit weight of water = 9.81 kN/m3
From data given we know that:
At 50% saturation,![\gamma_m = 16.62 kN/m3](https://tex.z-dn.net/?f=%20%5Cgamma_m%20%3D%2016.62%20kN%2Fm3)
puttng all value to get Gs value;
![16.62= \frac{(Gs+0.5*e)\timees 9.81}{(1+e)}](https://tex.z-dn.net/?f=16.62%3D%20%5Cfrac%7B%28Gs%2B0.5%2Ae%29%5Ctimees%209.81%7D%7B%281%2Be%29%7D)
Gs - 1.194*e = 1.694 .........(1)
for saturaion 75%, unit weight = 17.71 KN/m3
![17.71 = \frac{(Gs+0.75*e)\times 9.81}{(1+e)}](https://tex.z-dn.net/?f=17.71%20%3D%20%5Cfrac%7B%28Gs%2B0.75%2Ae%29%5Ctimes%209.81%7D%7B%281%2Be%29%7D)
Gs - 1.055*e = 1.805 .........(2)
solving both equations (1) and (2), we obtained;
Gs = 2.647
e = 0.7986
Answer:
<h2>Generator </h2>
Explanation:
A generator converts mechanical energy into electrical energy
Answer:
Absolute pressure=70.72 KPa
Explanation:
Given that Vacuum gauge pressure= 30 KPa
Barometer reading =755 mm Hg
We know that barometer always reads atmospheric pressure at given situation.So atmospheric pressure is equal to 755 mm Hg.
We know that P= ρ g h
Density of ![Hg=13600 \frac{kg}{m^3}](https://tex.z-dn.net/?f=Hg%3D13600%20%5Cfrac%7Bkg%7D%7Bm%5E3%7D)
So P=13600 x 9.81 x 0.755
P=100.72 KPa
We know that
Absolute pressure=atmospheric pressure + gauge pressure
But here given that 30 KPa is a Vacuum pressure ,so we will take it as negative.
Absolute pressure=atmospheric pressure + gauge pressure
Absolute pressure=100.72 - 30 KPa
So
Absolute pressure=70.72 KPa