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vekshin1
3 years ago
6

The frequency of which type of electromagnetic wave is just higher than that of visible light?

Physics
1 answer:
Reptile [31]3 years ago
3 0

When you sort the ranges of EM waves from lowest to highest frequency, the visible light range is just higher than infrared (think "below red") and just lower than ultraviolet (think "above violet").

Choice E.

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Answer:

distance

Explanation:

it is the distance traveled by light in one year

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Find the equivalent resistance of this
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Answer:

Re=160ohm

Explanation:

Step#1

Rt=R1+R2 ( because both are in series)

Rt=(100+220 ) ohm

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Step#2

Rt and R3 are parallel so,

Re= (Rt× R3) ÷ (Rt+R3)

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An object is placed perpendicular to the the principal axis of convex lens of focal length 8,the distance of the object from the
Digiron [165]

Answer:

v = 24 cm and inverted image

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Given that,

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\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

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\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{8}+\dfrac{1}{(-12)}\\\\v=24\ cm

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2 years ago
During takeoff, an airplane climbs with a speed of 195 m/s at an angle of 15° above the horizontal. The speed and angle constitu
matrenka [14]

Answer:

The horizontal component of the velocity is 188 m/s

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Hi there!

Please, see the figure for a graphic description of the problem. Notice that the x-component of the vector velocity (vx), the y-component (vy) and the vector velocity form a right triangle. Then, we can use trigonometry to obtain the magnitude of vx and vy:

We can find vx using the following trigonometric rule of a right triangle:

cos α = adjacent / hypotenuse

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The horizontal component of the velocity is 188 m/s

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The vertical component of the velocity is 50 m/s.

4 0
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