Answer:
Explanation:
Important here is to know that due north is a 90 degree angle, due east is a 0 degree angle, and due south is a 270 degree angle. Then we find the x and y components of each part of this journey using the sin and cos of the angles multiplied by each magnitude:
Add them all together to get the x component of the resultant vector, V:
Do the same to find the y components of the part of this journey:
Add them together to get the y component of the resultant vector, V:
One thing of import to note is that both of these components are positive, so the resultant angle lies in QI.
We find the final magnitude:
and, rounding to 2 sig dig's as needed:
1.0 × 10² m; now for the direction:
58°
Answer:
The position is relative to the base of the ocean
Explanation:
From the question we are told that
The angle made by the incline with the horizontal is
The constant acceleration is
The distance covered is
The height of the cliff is
The velocity of the car is mathematically represented as
The initial velocity of the car is u= 0
So
substituting values
The vertical component of this velocity is
substituting values
The negative sign is because is moving in the negative direction of the y-axis
The horizontal component of this velocity is
Now according to equation of motion we have
substituting values
using quadratic equation we have that
given that time cannot be negative
The car’s position relative to the base of the cliff when the car lands in the ocean is mathematically evaluate as
substituting values
The value of normal force as the slider passes point B is
The value of h when the normal force is zero
<h3>How to solve for the normal force</h3>
The normal force is calculated using the work energy principle which is applied as below
K₁ + U₁ = K₂
k represents kinetic energy
U represents potential energy
the subscripts 1,2 , and 3 = a, b, and c
for 1 to 2
K₁ + W₁ = K₂
0 + mg(h + R) = 0.5mv²₂
g(h + R) = 0.5v²₂
v²₂ = 2g(1.5R + R)
v²₂ = 2g(2.5R)
v²₂ = 5gR
Using summation of forces at B
Normal force, N = ma + mg
N = m(a + g)
N = m(v²₂/R + g)
N = m(5gR/R + g)
N = 6mg
for 1 to 3
K₁ + W₁ = K₃ + W₃
0 + mgh = 0.5mv²₃ + mgR
gh = 0.5v²₃ + gR
0.5v²₃ = gh - gR
v²₃ = 2g(h - R)
at C
for normal force to be zero
ma = mg
v²₃/R = g
v²₃ = gR
and v²₃ = 2g(h - R)
gR = 2gh - 2gR
gR + 2gR = 2gh
3gR = 2gh
3R/2 = h
Learn more about normal force at:
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So, physical properties are what we can detect with our basic 5 senses or measuring tools, and the things that, when changed, dont actually change the chemical properties (like atoms and molecules). Lets take wood for an example: its brown, its solid, it can be big or small, it has a taste and smell, its boiling, freezing or melting point...
Chemical properties, on the other hand, are the things we can change with, for example, experiments and tools. Does it burn? Can it rust/oxidize? How does it react with other chemicals? Is it radioactive, or toxic? All of these are chemical properties you can probably answer.