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Damm [24]
3 years ago
14

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

Physics
1 answer:
zloy xaker [14]3 years ago
6 0
Meter and second is the correct answer.
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A 500 Kg load is lifted through a vertical height of 10m in 25s by a crane. Calculate the power of the crane
denis23 [38]

Answer:

1962 W

Explanation:

P = W/t

P = F d cos theta / t

P = (500 kg) (9.81 m/s^2) (10 m) (cos 180) / 25 s  <-- the displacement and the force act in opposite directions (but it doesn't matter because direction doesn't matter in this case)

P = 1962 W

8 0
2 years ago
15 points!!!
AfilCa [17]
Use google cuz google is most intelligent than us


-Just sayin don’t get mad
5 0
3 years ago
Question Task: For each box, draw the strength of electric charge for objects with a negative charge. Label the boxes with one o
iogann1982 [59]

Answer:

Hope this helps

Explanation:

As we know our atmosphere or air have different levels. Every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

8 0
3 years ago
The polynomial 0.041h - 0.018A - 2.69 can be used to estimate the lung capacity, in liters, of a female with height h centimeter
Elden [556K]

Answer:

5 liters.

Explanation:

We are being given the expression

V = 0.041h - 0.018A - 2.69

The height h is 165 cm.

The Age A is 65 years old.

So we replace the values of h and A in the equation given:

V = 0.041 * 165 + 0.018 * 65 - 2.69 = 5.245 liters.

Rounding, we notice that 5.245 liters is closer to 5 than 6. So the answer would be 5 liters.

4 0
3 years ago
Can anyone tell me how to read a micrometer screw gauge I want very clear instructions.
Natalka [10]

Explanation:

Things you need to know:

Accuracy refers to the maximum error encountered when a particular observation is made.

Error in measurement is normally one-half the magnitude of the smallest scale reading.

Because one has to align one end of the rule or device to the starting point of the measurement, the appropriate error is thus twice that of the smallest scale reading.

Error is usually expressed in at most 1 or 2 significant figures.

Tape

Equipment: It is made up of a long flexible tape and can measure objects or places up to 10 – 50 m in length. It has markings similar to that of the rigid rule. The smallest marking could be as small as 0.1 cm or could be as large as 0.5 cm or even 1 cm.

How to use: The zero-mark of the measuring tape is first aligned flat to one end of the object and the tape is stretched taut to the other end, the reading is taken where the other end of the object meets the tape.

Ruler

Equipment: It is made up of a long rigid piece of wood or steel and can measure objects up to 100 cm in length. The smallest marking is usually 0.1 cm.

How to use: The zero-end of the rule is first aligned flat with one end of the object and the reading is taken where the other end of the object meets the rule.

Vernier Caliper

Equipment: It is made up of a main scale and a vernier scale and can usually measure objects up to 15 cm in length. The smallest marking is usually 0.1 cm on the main scale.

It has:

a pair of external jaws to measure external diameters

a pair of internal jaws to measure internal diameters

a long rod to measure depths

How to use: The jaws are first closed to find any zero errors. The jaws are then opened to fit the object firmly and the reading is then taken.

Micrometer Screw Gauge

Equipment: It is made up of a main scale and a thimble scale and can measure objects up to 5 cm in length. The smallest marking is usually 1 mm on the main scale (sleeve) and 0.01 mm on the thimble scale (thimble). The thimble has a total of 50 markings representing 0.50 mm.

It has:

an anvil and a spindle to hold the object

a ratchet on the thimble for accurate tightening (prevent over-tightening)

How to use: The spindle is first closed on the anvil to find any zero errors ( use the ratchet for careful tightening). The spindle is then opened to fit the object firmly (use the ratchet for careful tightening) and the reading is then taken.

5 0
3 years ago
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