The impact of the material
type with which the slope is made affects the acceleration. Acceleration will
be higher and smoother if the material of the slope surface is smoother as
opposed to a texture which is not smooth. Smoother surface allows more acceleration
because it will have less friction and resistance. Otherwise the friction will
slow the object down for example a grassy ground will have more friction than a
well maintained marble floor.
Answer:
259 Hz or 269 Hz
Explanation:
Beat: This is the phenomenon obtained when two notes of nearly equal frequency are sounded together. The S.I unit of beat is Hertz (Hz).
From the question,
Beat = f₂-f₁................ Equation 1
Note: The frequency of the other instrument is either f₁ or f₂.
If the unknown instrument's frequency is f₁,
Then,
f₁ = f₂-beat............ equation 2
Given: f₂ = 264 Hz, Beat = 5 Hz
Substitute into equation 2
f₁ = 264-5
f₁ = 259 Hz.
But if the unknown frequency is f₂,
Then,
f₂ = f₁+Beat................. Equation 3
f₂ = 264+5
f₂ = 269 Hz.
Hence the beat could be 259 Hz or 269 Hz
Answer:
V = 2.05× 10⁸ m/s
Explanation:
We are given;
The angle of the incidence; i = 40°
Angle of refraction; (r) = 26°
For us to find the speed of light in the material, we'll use Snell's law
From shell's law, we know that;
n = sin i/sin r = speed of light in air/Speed of light in the medium
Now, speed of light in air = 3 × 10⁸ m/s
Lets speed of light in medium be V
Thus, plugging in the relevant values to obtain;
Sin 40°/sin 26° = 3×10⁸/V
Let's make V the subject;
V = 3 × 10⁸× sin 26°/sin 40°
V = 2.05× 10⁸ m/s
Answer:
72 J
Explanation:
Total kinetic energy will be tge sum of rotational and translational energy.
Rotational kinetic energy is given by
where I is moment of inertia which is given by
and here m is mass, r is radius. Also,
hence making \omega the subject then
where v is the velocity.
Rotational kinetic energy=
This is same as the formula for translational kinetic energy which is given by 
Therefore, total kinetic energy= 
Substituting m with 2 kg and v with 6 m/s then total energy will be 