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garik1379 [7]
1 year ago
8

A current of 2.0 A flows through a circuit containing a motor with a resistance of 12 ohm how much energy is converted if the mo

tor runs for a minute
Physics
1 answer:
bearhunter [10]1 year ago
5 0

The energy converted is 48 Joules

<h3>How to determine the energy</h3>

We have the formula for energy in a circuit as

Energy = Power × time

Power = I^2 R

Current, I = 2.0 A

time = 1 minute

Resistance = 12 Ohm

Substitute into the formula

Power = 2 × 2 × 12

Power = 48 Watts

Energy = 48 × 1

Energy = 48 Joules

Thus, the energy converted is 48 Joules

Learn more about energy in a circuit here:

brainly.com/question/14950715

#SPJ1

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On the day Harvey is to present his dissertation, he wakes up with a severe headache. During the presentation, he feels no pain
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Gate-control theory

<h3>What is Gate-control theory?</h3>

According to the Gate Control Theory of Pain, the spinal cord has a system that allows pain signals to be amplified in the brain before being processed at the spinal cord itself, or attenuated there. 

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1 year ago
Les propriétés de l’air?
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Answer:

Lorsque l'on détend l'air son volume augmente et sa pression diminue. L'air qui est un mélange de gaz est compressible et expansible. – Lorsque l'on comprime l'air, son volume diminue et sa pression augmente. – Lorsque l'on détend l'air, son volume augmente et sa pression diminue.

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2 years ago
Who can help me for this question plz:(
Vanyuwa [196]
Force = mass x acceleration

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8 0
3 years ago
Show all work.
lys-0071 [83]

The new gravitation force at the new location is 40 N

Explanation:

The weight of the astronaut is given by the equation

F=mg (1)

where

m is the mass of the astronaut

g is the acceleration of gravity

The acceleration of gravity at a certain distance r from the centre of the Earth is given by

g=\frac{GM}{r^2}

where G is the gravitational constant and M is the Earth's mass. So we can rewrite eq.(1) as

F=\frac{GMm}{r^2}

When the astronaut is on the Earth's surface, r=R (where R is the Earth's radius), so his weight is

F=\frac{GMm}{R^2}=640 N

Later, he moves to another location where his distance from the Earth's surface is 3 times the previous distance, so the new distance from the Earth's centre is

r'=3R+R=4R

Therefore, the new weight is

F'=\frac{GMm}{(4R)^2}=\frac{1}{16}\frac{GMm}{R^2}=\frac{F}{16}

Which means that his weight has decreased by a factor 16: therefore, the new weight is

F'=\frac{640}{16}=40 N

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