Answer:
I'm pretty sure the answer is runoff
It would be 17 m/s
If we use
V2 = V1 + a*t
Sub in 5 for v1
2m/s*2 for a
And
6 for t
That should give you the answer.
Answer:
![M_1 = 317.7 kg](https://tex.z-dn.net/?f=M_1%20%3D%20317.7%20kg)
Explanation:
Mass of the helium gas filled inside the volume of balloon is given as
![m = \rho V](https://tex.z-dn.net/?f=m%20%3D%20%5Crho%20V)
![m = 0.179(\frac{4}{3}\pi R^3)](https://tex.z-dn.net/?f=m%20%3D%200.179%28%5Cfrac%7B4%7D%7B3%7D%5Cpi%20R%5E3%29)
![m = 0.179(\frac{4}{3}\pi 6.55^3)](https://tex.z-dn.net/?f=m%20%3D%200.179%28%5Cfrac%7B4%7D%7B3%7D%5Cpi%206.55%5E3%29)
![m = 210.7 kg](https://tex.z-dn.net/?f=m%20%3D%20210.7%20kg)
now total mass of balloon + helium inside balloon is given as
![M = 210.7 + 990](https://tex.z-dn.net/?f=M%20%3D%20210.7%20%2B%20990)
![M = 1200.7 kg](https://tex.z-dn.net/?f=M%20%3D%201200.7%20kg)
now we know that total weight of balloon + cargo = buoyancy force on the balloon
so we will have
![(M + M_1)g = \rho_{air} V g](https://tex.z-dn.net/?f=%28M%20%2B%20M_1%29g%20%3D%20%5Crho_%7Bair%7D%20V%20g)
![(1200.7 + M_1) = (\frac{4}{3}\pi 6.55^3) (1.29)](https://tex.z-dn.net/?f=%281200.7%20%2B%20M_1%29%20%3D%20%28%5Cfrac%7B4%7D%7B3%7D%5Cpi%206.55%5E3%29%20%281.29%29)
![1200.7 + M_1 = 1518.4](https://tex.z-dn.net/?f=1200.7%20%2B%20M_1%20%3D%201518.4)
![M_1 = 317.7 kg](https://tex.z-dn.net/?f=M_1%20%3D%20317.7%20kg)
As a reference, consider the line from the point perpendicular to the mirror.
That direction is called 'normal' to the mirror.
The ray on the right leaves the point traveling 5° to the right of the normal,
and leaves the mirror on a path that's 10° to the right of the normal.
The ray on the left leaves the point traveling 5° to the left of the normal,
and leaves the mirror on a path that's 10° to the left of the normal.
The angle between the two rays after they leave the mirror is 20° .
Frankly, Charlotte, if there were more than 5 points available for this answer,
I'd seriously consider giving you a drawing too.