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fenix001 [56]
3 years ago
7

Is this in standard form ? if it isn't then what would it be in standard form ?

Mathematics
2 answers:
Assoli18 [71]3 years ago
7 0
No...standard form cannot have fractions

2/3x - 1/3y = 2....multiply by common denominator of 3 to get rid of fractions
2x - y = 6 <== standard form
zloy xaker [14]3 years ago
6 0
Hello!

To answer your first question, no, that isn't in standard form.

For something to be in standard form, x can't be negative, both x and y need to be on the left side, and there can't be fractions.

Taking the three rules, let's make that equation have no fractions. In order to remove the fractions, you multiply everything by 3.

2/3x - 1/3y = 2
2x - y = 6

Let's go over the rules again to make sure:
X isn't negative - correct.
x and y is on the left side - correct
No fractions - correct.

Now that it passed all the rules, 2x - y = 6 would be your correct standard form equation.

Hope I helped (:
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Claire is a manager at a toy packaging company. The company packs 80 boxes of toys every hour for the first 3 hours of the day.
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Answer:

See the attached figure.

Step-by-step explanation:

Modeling each part as a function.

Let x is hours of the working day

The company packs 80 boxes of toys every hour for the first 3 hours of the day. ⇒ y₁ = 80 x , x ∈ [0,3]

At the end of the 3 hours The company packs = 80 * 3 = 240

They stop packaging for the next 2 hours in order to carry out a training session. ⇒ y₂ = 240 , x ∈ [3,5]

Then, for the next 4 hours, they pack 20 boxes of toys every hour

y₃ = 20x + c , x ∈ [5,9]

To find c, y₂ = y₃ at x =5

∴ 240 = 20 * 5 + c

∴ c = 240 - 20 * 5 =240 - 100 = 140

∴ y₃ = 20x + 140 , x ∈ [5,9]

So,

y₁ = 80 x , x ∈ [0,3]

y₂ = 240 , x ∈ [3,5]

y₃ = 20x + 140 , x ∈ [5,9]

The graph models the piecewise function for the given situation is as shown in the attached figure.

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Answer:

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Explanation:

<h3><u>Domain</u><u> </u><u>and</u><u> </u><u>Range:</u></h3>

Let R be a relation from A to B. Then the set of first components or the set of elements of A are called domain and the set of second components or the set of elements of B are called the range.

Hope this helps...

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Step-by-step explanation:

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