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Anna35 [415]
3 years ago
10

A body is acted upon by a force of 4N.

Physics
1 answer:
ladessa [460]3 years ago
7 0

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Kinematics.

so here we get as,

V^2 = U^2 + 2as

so here, a = -0.2 m/s^2

(0.1)^2 = (0.3)^2 + (-0.2)(s)

=> 0.01 = 0.09 - 0.2s

=> 0.2s = 0.08

=> s = 0.08/0.2

=> s = 0.4 m

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Vision is blurred if the head is vibrated at 29 Hz because the vibrations are resonant with the natural frequency of the eyeball
STALIN [3.7K]

The effective spring constant of the system is 39.6 N/m

Explanation:

The frequency of oscillation of a spring-mass system is given by

f=\frac{1}{2\pi}\sqrt{\frac{k}{m}}

where

k is the spring constant of the system

m is the mass

In this problem, we have:

f = 29 Hz is the frequency of vibration of the eyeball system

m = 7.5 g = 0.0075 kg is the mass

We can therefore re-arrange the equation to find the effective spring constant of the system. We find:

k=(2\pi f)^2 m = (2\pi (29))^2 (0.0075)=39.6 N/m

#LearnwithBrainly

4 0
3 years ago
An electronic device can be modeled as a resistor that consumes an average of about 0.940 W of electrical power and operates on
nirvana33 [79]

Answer:

Ans= d 1.02 you add and multiple

5 0
3 years ago
How do you know that Earth is affected by the gravitational pull of the sun ? Explain how you would be affected if you were able
Assoli18 [71]

Answer:

The Sun's gravity pulls on the planets, just as Earth's gravity pulls down anything that is not held up by some other force and keeps you and me on the ground.

Explanation: Newton realized that the reason the planets orbit the Sun is related to why objects fall to Earth when we drop them. I am so sorry if I get this wrong, I'm in 5th grade! ♥

6 0
3 years ago
now suppose that we have attached not just two springs in series, but N springs. Write an equation that expresses the effective
sammy [17]

Answer:

 k_{eq} = \frac{k}{N}

Explanation:

For this exercise let's use hooke's law

         F = - k x

where x is the displacement from the equilibrium position.

        x = - \frac{F}{k}

if we have several springs in series, the total displacement is the sum of the displacement for each spring, F the external force applied to the springs

       x_ {total} = ∑ x_i

we substitute

       x_ {total} =  ∑ -F / ki

       F / k_ {eq} =  -F  \sum \frac{1}{k_i}

      \frac{1}{k_{eq}} = \frac{1}{k_i} 1 / k_ {eq} =  ∑ 1 / k_i

if all the springs are the same

     k_i = k

     \frac{1}{k_{eq}} = \frac{1}{k} \sum 1 \\

     \frac{1}{k_{eq} } =  \frac{N}{k}

     k_{eq} = \frac{k}{N}

6 0
3 years ago
The Achilles tendon connects the muscles in your calf to the back of your foot. When you are sprinting, your Achilles tendon alt
Andrews [41]

Explanation:

It is given that,

Mass of the runner, m = 70 kg

Length of the tendon, l = 15 cm = 0.15 m

Area of cross section, A=110\ mm^2=0.00011\ m^2

Part A,

Let the runner's Achilles tendon stretch if the force on it is 8.0 times his weight, F = 8 mg

Young's modulus for tendon is, Y=0.15\times 10^{10}\ N/m^2

The formula of the Young modulus is given by :

Y=\dfrac{F/A}{\dfrac{\Delta L}{L}}

0.15\times 10^{10}=\dfrac{8\times 70\times 9.8/0.00011}{\dfrac{\Delta L}{0.15}}

\Delta L=0.0049\ m

Part B,

The fraction of the tendon's length does this correspond is given by :

\dfrac{\Delta L}{L}=\dfrac{0.0049}{0.15}

\dfrac{\Delta L}{L}=0.0326

Hence, this is the required solution.

6 0
3 years ago
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