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Anna35 [415]
3 years ago
10

A body is acted upon by a force of 4N.

Physics
1 answer:
ladessa [460]3 years ago
7 0

\mathfrak{\huge{\pink{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Kinematics.

so here we get as,

V^2 = U^2 + 2as

so here, a = -0.2 m/s^2

(0.1)^2 = (0.3)^2 + (-0.2)(s)

=> 0.01 = 0.09 - 0.2s

=> 0.2s = 0.08

=> s = 0.08/0.2

=> s = 0.4 m

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Answer:

3 and 2

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ok may be subscribeIsenberg Isenberg Ignatius

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A spring of negligible mass and force constant k = 430 N/m is hung vertically, and a 0.270 kg pan is suspended from its lower en
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A spring whose spring constant is 270 lbf/in has an initial force of 100 lbf acting on it. Determine the work, in Btu, required
cricket20 [7]

Answer:

0.02585 BTU

Explanation:

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Compression, x = 1 in

Work done can be calculated as follows:

W = \int {(f+kx)} \, dx \\W = fx + \frac{1}{2}kx^2\\W= (100 lbf)(1 in)+ \frac{1}{2}(270 lbf/in)(1 in)^2\\W= 100+135 = 235 lbf in\\W=235 \times 0.00011 BTU = 0.02585 BTU

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3 years ago
Read 2 more answers
A positive charge is moved from point A to point B along an equipotential surface. How much work is performed or required in mov
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Answer:

No work is performed or required in moving the positive charge from point A to point B.

Explanation:

Lets take

Q= Positive charge which move from  point A to point B along

Voltage difference,ΔV =V₁ - V₂  

The work done

W = Q . ΔV

Given that  charge is moved from point A to point B along an equipotential surface.It means that voltage  difference is zero.

ΔV = 0

So

W = Q . ΔV

W = Q x 0

W= 0 J

So work is zero.

5 0
3 years ago
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